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algebraic quantities antecedent apples arithmetical arithmetical means arithmetical progression binomial called cents Charles Clear the equation co-efficient common difference complete equation completing the square consequent contain contrary signs cube denote the number dividend division divisor dollars equation x² EXAMPLES exponent extracting the square Find the factors Find the square Find the sum Find the values find three numbers following RULE four fraction geometrical progression give a sum Give the rule given number greater Hence James John last term least common multiple letter logarithm metical mixed quantity monomial negative number added number of terms obtain ounces perfect square polynomial proportion quotient radical sign ratio remainder second degree second term simplest form square root Substituting this value sum equal third transposing twice the product units unknown quantity Verification whence yards Зах
Page 69 - Then divide the first term of the remainder by the first term of the divisor...
Page 16 - Similarly, any term may be transposed from one member of an equation to the other by changing its sign.
Page 248 - That is : The first term of an increasing arithmetical progression is equal to the last term, minus the product of the common difference by the number of terms less one.
Page 255 - Three quantities are in proportion when the first has the same ratio to the second, that the second has to the third ; and then the middle term is said to be a mean proportional between the other two.
Page 162 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 257 - Of four proportional quantities, the product of the two extremes is equal to the product of the two means.
Page 160 - Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Page 88 - To find a number which, being added to itself, shall give a sum equal to 30. Were it required to solve this problem we should first express it in algebraic language, which would give the equation x+ x= 30. By adding x to itself, we have 2x=SO. and by dividing by 2, we obtain .... x= 15.