 | Jeremiah Paul - Arithmetic - 1801 - 238 pages
...table of po/wers ; involve it as often as is indicated by the power, and subtract the product frem the left hand period ; and to the remainder bring down the first figure in the next period for a dividend. 3. Involve the root to the next inferior power to that roentioned... | |
 | Arithmetic - 1811 - 210 pages
...root. 2. Find the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the- remainder bring down the first figure in the next period for a dividend. 3. Involve the root to the next inferior power to that which is... | |
 | Arithmetic - 1817 - 214 pages
...contained in the left hand period, and set its root on the right of the given number : subtract said cube from the left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root and multiply the square by 3 for a defective divisor.... | |
 | Daniel Staniford - Arithmetic - 1818 - 332 pages
...requires. 2. Find the first figure in the root, and subtract its power from the given number, and lo the remainder bring down the first figure of the next period and call it the dividend. 3. Involve the root already found to the power next inferior to that which is given,... | |
 | Jacob Willetts - Arithmetic - 1822 - 200 pages
...root. 2. Find the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividual. 3. Involve the root to the next inferior power to that which is... | |
 | Stephen Pike - Arithmetic - 1824 - 212 pages
...contained in the left hand period, and set its root on the right of the given number: subtract said cube from the left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root and multiply the square by 3 for a defective divisor.... | |
 | Warren Colburn - Algebra - 1825 - 400 pages
...left hand period, and write the root in the place of a quotient* Subtract the power from the period. To the remainder bring down the first figure of the next period for a dividend. Multiply the second power of the root already found, by three to form a divisor. See... | |
 | Zachariah Jess - Arithmetic - 1827 - 226 pages
...from the number of periods in the given number, as are represented by the last figure brought down. 8. To the remainder, bring down the first figure of the next period, for a new dividend. 9. Find a new divisor, as betöre, and thus proceed to the end, EXAMPLES. 1. What... | |
 | Martin Ruter - Arithmetic - 1828 - 180 pages
...Find the greatest cube in the left hand period, place the root of it in the quotient, subtract the cube from the left hand period, and to the remainder bring down the next period for a resolvend. 3. Square the quotient, and multiply the square by 3 for a defective divisor.... | |
 | Warren Colburn - Algebra - 1828 - 330 pages
...left hand period, and write the root in the place of a quotient. Subtract the power from the period. To the remainder bring down the first figure of the next period for a dividend. Multiply the second power of the root already found by three, to form a divisor. See... | |
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Subtract the cube of this number from the first period, and to the remainder bring down the first figure of the next period for a dividend. 
