 | Mathematics - 1801 - 658 pages
...conoid, whose altitude is 42, and the diameter of its base 24 ? Ans. PROBLEM PROBLEM xxvn. To fold the solidity of the frustum of a paraboloid. RULE....the squares of the diameters of the two ends by the heightj and the product by '3927, for* the content. ' ., . • i. Required the co.ntent of the p'ar'aboloidal... | |
 | Samuel Webber - Mathematics - 1808 - 520 pages
...of a parabolic conoid, whose altitude is 42, and the diameter of its base 24 ? PROBLEM XXVII. Tofnd the solidity of the frustum of a paraboloid. RULE....of the diameters of the two ends by the height, and the product by '3927, for the content. EXAMPLES. 1. Required the content of the paraboloidal frustum... | |
 | Nicolas Pike - Algebra - 1808 - 470 pages
...Conoid. Definition. This solid is made by a plane passing through the conoid, parallel to its base. RULE. — Multiply the sum of the squares of the diameters of the bases by '7^54, and that product by half the hejght, for*the solidity. If the diameters of a frustum... | |
 | Thomas Keith - 1817 - 306 pages
...&c. MENSURATION OF SOLIDS. PROBLEM XXII. To find the Solidity of the Frustum of a parabolic Conoid. i RULE *. Multiply the sum of the squares of the diameters of the two cuds by the height, and that product by '3927 for the solidity. Note. This rule is useful in caskgauging.... | |
 | William Hawney - Geometry - 1820 - 336 pages
...base 32 ? .4ns. 9188.55168. To find the Sulidity of the Frustum of a Paraboloid, or J'arabolic Conoid. RULE. Multiply the sum of the squares, of the diameters of the two ends by the height, aud by .7854, half the product will be the solidity. NOTK. This rule is useful in cask-<ruagin2;. For... | |
 | Anthony Nesbit - Surveying - 1824 - 476 pages
...Tojindthe solidity ofthefmstum of a paraboloid, taken its ends are perpendicular to the axis of the solid. RULE. Multiply the sum of the squares of the diameters of the two ends by the height of the frustum, and the product thus obtained by .3927 ; and the last product will be the solidity.... | |
 | John Bonnycastle - Geometry - 1829 - 256 pages
...solidity of the frustum of a paraboloid, u-hcn its ends are perpendicular to the axe of the solid. RULE.* Multiply the sum of the squares of the diameters of the two ends by the height of the frustum, and the product again by .3927, and it will give the solidity. EXAMPLES. 1. Required... | |
 | John Bonnycastle - Measurement - 1833 - 310 pages
...fritstrum of a paraboloid then its ends are perpendicular to the axe of the solid p ' . " . * •"• RULE.* Multiply the sum of the squares of the diameters of the wo ends by the height of the frustrum, and the product gain by .3927, and it will give the solidity.... | |
 | Tobias Ostrander - Measurement - 1833 - 172 pages
...frustrum of a paraboloid, when its ends are perpendicular to the axis of the solid. Rule—Multiply the sum of the squares of the diameters of the two ends by ; the height of the frustrum, and the product by ,3927 and it will give the solidity. EXAMPLES. 1. Required the... | |
 | Ireland commissioners of nat. educ - 1834 - 370 pages
...its base 8 ? Ans. 753-984. PROBLEM XXII. To find the solidity ofthefrusfrum of a parabolic conoid. RULE. Multiply the sum of the squares of the diameters...of the two ends by the height, and that product by -3929 ; the last product will be the solidity .-(• * Demonstration. It was proved in Prop. VIII.... | |
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RULE.* Multiply the sum of the squares of the diameters of the two ends by the height of the frustum, and the product again by .3927, and it will give the solidity. 
