 AREAS. 175. Definitions. Equivalent figures, area of a figure, units of area, transformation of a figure. 176. Theorem. Two rectangles having equal bases are to each other as their altitudes; and two rectangles having equal altitudes are to each other...  Wentworth & Hills's Exercise Manuals: Geometry - Page xxiiiby George Albert Wentworth - 1889Full view - About this book
 | George Albert Wentworth - 1884 - 264 pages
...construct upon a given line a polygon similar to a given polygon. BOOK IV. EQUIVALENT FIGURES. AREA3. 175. Definitions. Equivalent figures, area of a figure,...other as their bases. 182. Theorem. Area of a triangle = $ base X altitude. 184. Theorem. Area of a trapezoid = J sum of the bases X altitude. 185. Theorem-.... | |
 | George Albert Wentworth - 1886 - 264 pages
...Theorem. In an obtuse triangle the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice...base X altitude. 184. Theorem. Area of a trapezoid = i sum of the bases X altitude. 185. Theorem. Area of a trapezoid = median X altitude. 186. Theorem.... | |
 | George Albert Wentworth - 1886 - 268 pages
...three given lines. 169. To find the third proportional to two given lines. 171. To divide one side of.a triangle into two parts proportional to the other...other as their bases. 182. Theorem. Area of a triangle = \ base X altitude. 184. Theorem. Area of a trapezoid = J sum of the bases X altitude. 185. Theorem.... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry, Modern - 1896 - 276 pages
...equal bases are to each other as their altitudes. axb (P_ _a X b _a \ ~P'~ a'x6~'a'') 389. COR. IV. Two parallelograms having equal altitudes are to each other as their bases. axb b yP _aX6 _b \P'~ axb'~'b' PROPOSITION VI. THEOREM 3904 The area of a triangle equals one-half... | |
 | Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 570 pages
...parallelograms having equal bases are to each other as their altitudes. ' P axba ; P_ _a X b _a 389. COR. IV. Two parallelograms having equal altitudes are to each other as their bases. ax* b PROPOSITION VI. THEOREM 390. The area of a triangle equals one-half the product of its base and... | |
 | George Albert Wentworth - 1898 - 266 pages
...Theorem. In an obtuse triangle the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice...other as their bases. 182. Theorem. Area of a triangle = i base X altitude. 184. Theorem. Area of a trapezoid = J sum of the bases X altitude. 185. Theorem.... | |
 | Arthur A. Dodd, B. Thomas Chace - Geometry - 1898 - 490 pages
...two parallelograms having equal bases and equal altitudes are equivalent. 259. Cor. III. Show that two parallelograms having equal altitudes are to each other as their bases ; two parallelograms having equal bases are to each other as their altitudes; and any two parallelograms... | |
 | Webster Wells - Geometry - 1898 - 284 pages
...Two parallelograms having equal bases and equal altitudes are equivalent (§ 303). 311. Cor. II. 1. Two parallelograms having equal altitudes are to each other as their bases. 2. Two parallelograms having equal bases are to each other as their altitudes. 3. Any two parallelograms... | |
 | Webster Wells - Geometry - 1899 - 450 pages
...Two parallelograms having equal bases and equal altitudes are equivalent (§ 303). 311. Cor. II. 1. Two parallelograms having equal altitudes are to each other as their bases. 2. Two parallelograms having equal bases are to each other as their altitudes. 3. Any two parallelograms... | |
 | Charles Austin Hobbs - Geometry, Plane - 1899 - 266 pages
...III. Any two parallelograms are to each other as the products of their bases and altitudes. COB. IV. Two parallelograms having equal altitudes are to each other as their bases. Ex. 511. Upon the same base, to construct a rectangle equivalent to a given parallelogram. Ex. 512.... | |
| |
