The Millwright and Engineer's Pocket Companion

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Simpkin, Marshall and Company, 1846 - Mathematics - 220 pages
 

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Page 83 - ... one of the most important, and at the same time, one of the least expensive and troublesome, which we possess.
Page 36 - The areas of circles are to each other as the squares of their diameters.
Page 30 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 75 - To find the solidity of a spheroid. RULE. Multiply the square of the revolving axis by the fixed axis, and by *5236, and the product will be the solidity.
Page 66 - Area of a circle is equal to the area of a triangle whose base equals the circumference and perpendicular equals the radius.
Page 25 - RULE. — Multiply the difference between the root of the integer part of the given number, and the root of the next higher integer number, by the decimal part of the given number, and add the product to the root of the integer number given, the sum is the root required.
Page 96 - These simple machines are the lever, the wheel and axle, the pulley, the inclined plane, the wedge, and the screw.
Page 61 - NOTE. — 1. As 7 is to 22, so is the diameter to the circumference; or, as 22 is to 7, so is the circumference to the diameter.
Page 96 - ... that there may be a balance between the power and the weight, the intensity of the power must exceed the intensity of the weight just as much as the distance of the weight from the prop exceeds the distance of the power.

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