 BAE; and they are in one plane, which is impossible. Also, from a point above a plane, there can be but one perpendicular to that plane ; for, if there could be two, they would be parallel (6. PI.) to one another, which is absurd. Therefore, from the...  Books 10-13 and appendix - Page 295by Euclid - 1908Full view - About this book
 | Robert Simson - Trigonometry - 1762 - 488 pages
...the smgle CAE is equal to the angle BAE; and they are in one plane, D A which is impoiTible. Alfo, from a point above a plane there can be but one perpendicular to that plane; for if there could be two, l,. 6. ii. they would be parallel b to one another, which is abfurd. Therefore from the fame point,... | |
 | Robert Simson - Trigonometry - 1775 - 534 pages
...Wherefore the angle CAE is equal to the angle BAE ; and they are in one plane, which is impoflible. Affo, from a point above a plane, there can be but one perpendicular to that plane j for, if there could be two, they would be parallel b to one another, which is abfurd. Therefore,... | |
 | Euclid - 1781 - 552 pages
...equal to the angle BAE ; and they are in one plane, which is impoffible. Alfo, from a point n. bove a plane, there can be but one perpendicular to that...for, if there could be two, they would be parallel b to one another, which is abfurd. Therefore, from the fame point, &c. D PROP. XIV. THEO R. to which... | |
 | Euclid, John Playfair - Euclid's Elements - 1795 - 462 pages
...CAE is equal to the angle BAE ; and they are in j5"~ ' A. "j3 one plane, which is impoffible. Alfo, from a point above a plane, there can be but one perpendicular to that. plane; for, if there could be two, they P 4 would okyn. would be parallel b to one another, which is abfurd. There 6/7." f°re, fr°mt*16 fame... | |
 | Robert Simson - Trigonometry - 1804 - 530 pages
...CAE is equal to the angle — BAE; and they are in one plane, -A* .A. JLJ which is impofllble. Alfo, from a point above a plane there can be but one perpendicular...for if there could be two, they would be parallel b to one another, which is abfurd. Therefore from the fame point, &c. Q^ED 6. it. P PROP. XIV. THEOR.... | |
 | Robert Simson - Trigonometry - 1806 - 546 pages
...Wherefore BC the ahgle CAE is equal to the angle BAE; and they are in one plane, which is impossible. Also, from a point above a plane, there can be but...that plane ; for, if there could be two, they would b 6. 11. be parallel b to one another, which . is absurd. Therefore, from the same point, &c. JJ *s... | |
 | Euclid - Geometry - 1810 - 554 pages
...Wherefore the angle CAEis equal to theangle BAE; and they are in one plane, ( vhich is impossible. Also, from a point above a plane, there can be but one perpendicular to I hat plune ; for, if there could be two, they ~ — would be parallelh to one another, "• . *. which... | |
 | Euclides - 1814 - 560 pages
...reason liAE is a right angle. Where- • the angle BAE ; and they are in one plane, which is impossible. Also, from a point above a plane, there can be but...perpendicular to that plane: for, if there could be b 6.1i. two, they would be parallel b to one another, which is absurd. Therefore, from the same point,... | |
 | Euclides - 1816 - 588 pages
...Wherefore the angle CAE is equal to D~ A ^ the angle BAE; and they arc in one plane, which is impossible. Also, from a point above a plane, there can be but...for, if there could be two, they would be parallel b to one another, which is absurd. Therefore, from the same point, &c. QED PROP. XIV. THEOR. 1: PLANES... | |
 | John Playfair - 1819 - 354 pages
...Wherefore the angle CAE is equal to the angle BAE ; and they are in one plane, which is impossible. Also, from a point above a plane, there can be but...for if there could be two, they would be parallel (6. 2. Sup.) to one another, which is absurd. Therefore, from the same point, &c. Q, ED PROP. XII.... | |
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