 The sine of any middle part is equal to the product of the tangents of the Adjacent parts. RULE II. The sine of any middle part is equal to the product of the cosines of the opposite parts.  The Elements of Plane Trigonometry - Page 7by Henry Nathan Wheeler - 1878 - 112 pagesFull view - About this book
 | William Chauvenet - 1852 - 268 pages
...middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. The correctness of these rules will be shown by taking each of the five parts as middle part, and comparing... | |
 | Charles Davies, William Guy Peck - Mathematics - 1855 - 628 pages
...middle pari is equal to the products of the tangents of the adjacent parís. 2. The tine of the muidle part is equal to the -product of the cosines of the opposite part* : thus, sin (90° - «) = tan (90° - B) tan (90° - C), and sin (90° — it) = cos e cos 4.... | |
 | George Roberts Perkins - Geometry - 1856 - 460 pages
...middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five parts as the middle part, and apply these Eules, we shall obtain... | |
 | Horatio Nelson Robinson - Geometry - 1860 - 470 pages
...equal to the product of the tangents of the adjacent parts. 2. The radius into the sine of the middle part is equal to the product of the cosines of the opposite parts. These rules are known as .Napier's Rules, because they were first given by that distinguished mathematician,... | |
 | George Roberts Perkins - Geometry - 1860 - 472 pages
...middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five parts as the middle part, and apply these Rules, we shall obtain... | |
 | Benjamin Greenleaf - Geometry - 1862 - 532 pages
...middle part is equal to Hie product of tlte tangents of the adjacent parts. IL The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the results already established,... | |
 | Benjamin Greenleaf - Geometry - 1862 - 518 pages
...middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the results already established,... | |
 | Benjamin Greenleaf - Geometry - 1863 - 504 pages
...middle part is equal to the product of the tangents of the adjacent parts. . II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 168. Napier's rules may be proved by showing that they agree with the results already established,... | |
 | Gerardus Beekman Docharty - Geometry - 1867 - 474 pages
...to the product of the tangents of the adjacent parts. . 2. The product of sin. M and tabular radius is equal to the product of the cosines of the opposite parts. In order to make these rules clearly understood, we will show the manner in which they are applied in... | |
 | Edwin Pliny Seaver - Mathematics - 1871 - 78 pages
...as parts, the ten equations, (175) - (184), may be embodied in the following mnemonic rules : — I. The sine of any part is equal to the product of the tangents of the adjacent parts. II. The sine of any part is equal to the product of the cosines of... | |
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