| Zachariah Jess - Arithmetic - 1824 - 228 pages
...product is the last term or greater extreme. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio less one ; the quotient will be the sum of the series. EXAMPLES. 1 Sold 24 yards of Holland, at 2d. for... | |
| Zachariah Jess - Arithmetic - 1827 - 226 pages
...term. Then to find the sum of all the terms, multiply the last term by the ratio ; from the product, subtract the first term, and divide the remainder by the ratio, less one ; the quotient will be the sum of all the terms. Or shorter t thus : Involve the ratio to the power... | |
| Thomas Tucker Smiley - 1830 - 188 pages
...term, and that product will be the last term. 3. Multiply the last term by the ratio; from the pro duct subtract the first term, and divide the remainder by the ratio, less 1, for the sum of the series. Questions. What is Geometrical Progression? What is the ratio ? By what... | |
| Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...the series, we have the following easy HULE. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. ft If the extremes be 5 and 6400, and the ratio... | |
| Charles Potts - Arithmetic - 1835 - 202 pages
...the first | term, will give the last term. 2. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio less 1, for the sum of the series. EXAMPLES. 1. A labourer wrought 20 days, and received for the first day's... | |
| Roswell Chamberlain Smith - Arithmetic - 1836 - 308 pages
...the Series, we have the following easy RULE. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. 9. If the extremes be 5 and 6400, and the ratio... | |
| A. Turnbull - Arithmetic - 1836 - 368 pages
...extending the series to one more than the given term, and from the last term of the series thus extended, subtract the first term, and divide the remainder by the ratio, less 1. The reason for this rule may be explained thus : * = 8 + 24 + 72 + 216 + 648 + 1944. . If we multiply... | |
| Arithmetic - 1838 - 218 pages
...given, to find the sum of the series. RULE. — Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio less I, the quotient will be the sum of the series. The reason of the rule may be shown in the following... | |
| Roswell Chamberlain Smith - 1839 - 308 pages
...Series, we have the following easy «rf RULE. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. 9. If the extremes be 5 and 6400, and the ratio... | |
| Joseph Stockton - Arithmetic - 1839 - 216 pages
...will be the last term, or greater extreme. 2. Multiply the last term by the ratio, from that product subtract the first term, and divide the remainder by the ratio, less one ; the amount will be the sum of the series, or of all the terms. EXAMPLE. 1. Suppose 20 yards of... | |
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