 | Frederick Walter Simms - Leveling - 1856 - 258 pages
...Rule 1. — Subtract the angle of deflection from 180°, then say, As nat. sine of angle of deflection is to nat. sine of half the remainder, so is the given...the radius required. Example. — Let the angle of deflection be 2°, and the chord 100 feet; required the radius. Here, 2° subtracted from 180° leaves... | |
 | Whiting Griswold - Railroad engineering - 1866 - 144 pages
...radius corresponding to any given angle of deflexion, and to equal chords of any given length. RULE 18. Subtract the angle of deflexion from 180°; then say...remainder, so is the given chord to the radius required. Fig. 2. h With the chord and versed sine given, to find the radius. RUJE.E 19. The square of half the... | |
 | Electronic journals - 1851 - 498 pages
...chord at m, and lay off the tangential angle mtr, of the curve mn t; then from the common tangent rt s, lay off the tangential angle sto, of the curve tio;...89°, and as Nat. Sine of 2° . Nat. Sine of 89° . . Chord . Radius •034899 ••999848 •• 100 feet »2865feet. . Rule 2. The radius of 100 feet... | |
 | Electronic journals - 1881 - 668 pages
...Subtract angle of deflection from 180° then say as natural sine of angle of deflection is to natural sine of half the remainder so is the given chord to...the radius required. Example. — Let the angle of deflection be 0° 01', chord 100 feet (as usual in the table), required the radius. 180° — 0° 01'... | |
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... sto, of the curve tio; making at the same time the chord to, equal to 100 feet. NB — If running the curve by eye, use the tangential distances, instead of the angles. ARTICLE XV. — RADII. To find the radius corresponding to any given angle of... 