 | Samuel YOUNG (of Manchester.) - 1833 - 272 pages
...of the Products by three times the sura of the whole weight; the square root of the Quotient will be the distance of the centre of gyration from the centre of motion. (1) A bar, of uniform density, 12 feet long, and each foot weighing 7 Ibs. and revolving upon a centre... | |
 | Luke Hebert - Industrial arts - 1835 - 816 pages
...the sum of the products by the weight of the whole mass, and the square root of the quotient will be the distance of the centre of gyration from the centre of motion. CENTRE OF OSCILLATION is that point in a body suspended from a point and made to vibrate, in which... | |
 | William Grier - Mechanical engineering - 1836 - 384 pages
...from the centre, to generate that velocity? 6 X 2 X 10 120 = = -1562 of a t0" = 3 cwt. 1-49G rWhat is the distance of the centre of gyration from the centre of motion of a fly-wheel, the force which moves the wheel being 2 cwt., acting at the distance of 7 feet from the... | |
 | Luke Hebert - Industrial arts - 1836 - 814 pages
...the sum of the products by the weight of the whole mass, and the square root of the quotient will be the distance of the centre of gyration from the centre of motion. CENTRE OF OSCILLATION is that point in a body suspended from a point and made to vibrate, in which... | |
 | William Grier - Mechanical engineering - 1842 - 320 pages
...must be applied for 8 seconds, at the distance of 3 feet from the centre, to generate that velocity ? What is the distance of the centre of gyration from the centre of motion of a fly-wheel, the force which moves the wheel being 2 cwt., acting at the distance of 7 feet from the... | |
 | W. H. CRANK - Arithmetic - 1843 - 340 pages
...the centre of gyration is = 18 x -6324= 11-3832 inches. (2) There is a rod 82'3 inches long. Required the distance of the centre of gyration from the centre of motion. Ans. 47-32825 inches. It was intended to have introduced a short treatise on the Mechanical Powers... | |
 | Charles Haynes Haswell - Engineering - 1844 - 298 pages
...upon a lever (which is here assumed to be without weight) at the respective distances of 1 and 2 feet, what is the distance of the centre of gyration from the centre of motion (the fulcrum) ? 3X12 = 3. = = 2.71, and .^2.71 = 1.64 feet, Ana. That is, a single weight of 7 Ibs.,... | |
 | Artizan club (London, England) - Steam engineering - 1847 - 338 pages
...ascertained. ID a right line, or a cvlinder of very small diameter revolving about one of its extremities, the distance of the centre of gyration from the centre of motion is equal to the length of the revolving Tine or cylinder multiplied by the Hjuare root of I. In the... | |
 | Charles Haynes Haswell - Engineering - 1851 - 346 pages
...upon a lever (which is here assumed to he without weight) at the respective distances of 1 and 2 feet, what is the distance of the centre of gyration from the centre of motion (the fulcrum) 1 3. 4X2= = 16. — = 2.71, and ^2.71 = 1.64 feet, Ans. That is, a single weight of 7... | |
 | Oliver Byrne - Engineering - 1851 - 310 pages
...ascertained. In a right line, or a cylinder of very small diameter revolving about one of its extremities, the distance of the centre of gyration from the centre of motion is equal to the length of the revolving line or cylinder multiplied by the square root of J. In the... | |
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... the square root of the quotient will be the distance of the centre of gyration, from the centre of motion. 
