...to find the other Extreme, and the Sum of the Series. -'..•' MULTIPLT the common difference by 1 less than the number of terms, and the product will be the difference of the extremes : Therefore add the product to the less extreme, to give the greater ; or...

...of Terms : to find the other Extreme, andthe Sum of the Series. MULTIPLY the common difference by I less than the number of terms, and the product will be the difference of the extremes: Therefore add the product to the less extreme, to give the greater ; or...

...that is, 439. In geometrical progtession, the greatest term it equal to the product of the least, into that, power of the ratio whose index is one less than the number of terms. When the least term and the ratio are the same, ihe equation becomes z=rrn~i=rn. See art. 437. 440....

...tlie 8th term •would be 2X2T, ami so on. In nu ascending scries, therefore, multiply tlie first t?rm by that power of the ratio whose index is one less than the number of tlie term sought, and the product is tlie terni tough! . In a descending series, as 213, 81,27,9,3,...

...2X2X2X2X?, &e. or thus 2, 2X2>, 8X?a, 2X21. 2X2-', anil so on. Any term alter the first is evidently that power of the ratio whose index is one less than the number of the term multiplied by the lint term. Thus, the 3d term is 2x2^ ; the 4th term is2X2:1, aud the ittli...

...of Terms ; to find the other Extreme, and the sum of the Series. MULTIPLY the common difference by 1 less than the number of terms, and the product will be the difference of the extremes : Therefore add the product to the less extreme, to give the greater ; or...

...that is, 439. In geometrical progression, the last term is equal to the product of the Jirst, into that power of the ratio whose index is one less than the number of terms. When the least term and the ratio are the same, the equation becomes z^=rr»~ =r". See art. 437. 440....

...1th term is 2X0 ! , ai.d the 8th term would be 2X27, nnd so on. In an asvending series, therefore, multiply the first term by that power of the ratio whose index is one less, than the number of the term sought, anil the product is the term sought. In a descending scries, as 243, 81, 27, '.',...

...s X2*=8X 16=128. Ans. I. The first term and ratio given to find any other term. RULE. — Find the power of the ratio, whose index is one less than the number of the required term, and multiply this power. by the first term, the product will be the answer, if the...

...27=23X24=8X16=128. Ans. I. The first term and ratio given to find any other term. RULE. — Find the power of the ratio, whose index is one less than the number of the required term, and multiply this power by the first term, the product will be the answer, if the...