The gunner's assistant

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Page 32 - ... weight, so is the specific gravity of water to the specific gravity of the body.
Page 21 - ... or, to three times the square of the radius of the. segment's base add the square of its height, then multiply the sum by the height, and this product by .5236, for the content.
Page 13 - If the rocket is to be used as a shell-rocket at the longest range, the plug is to be taken out, and the shell filled, the fuze left at its full length, and the plug replaced. If at the shortest range, the fuze is to be entirely bored through, and the rocket composition bored...
Page 32 - the mass compounded of the two may sink together. Weigh the denser body, and the compound mass separately, both in water, and out of it; then find how much, each loses, in, water, by subtracting its 'weight 'in water from its weight in air ; and subtract the less of these remainders from the greater.
Page 32 - Specific gravity denotes the relative, or comparative gravity of any body, in respect to that of another body of equal bulk, or magnitude. Centre of gravity is that point in a body, or system of bodies, on which, if rested, or suspended, the whole would remain in a state of equilibrium about that point. The centre of gravity of a circle, regular polygon, prism, cylinder, or sphere, is in its centre. The centre of gravity of a triangle is found by bisecting any two of its sides, and drawing lines...
Page 19 - So that, universally, shot which are of different weights, and impelled by the firing of different quantities of powder, acquire velocities which are directly as the square roots of the quantities of powder, and inversely as the square roots of the weights of the shot, nearly.
Page 26 - Lay a dram of it on a piece of clean writing-paper, and fire the heap by means of a red-hot iron wire : if the flame ascend quickly with a good report, leaving the paper free from white specks, and without burning holes in it, the goodness of the ingredients, and proper manufacture of the powder may be safely inferred.
Page 21 - ... -5236, for the content. RULE II. To 3 times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by -5236, for the content.
Page 21 - To find the side of a cubical box to contain a given quantity of powder.* Multiply the weight in pounds by 30, and the cube root of the product will be the side of the box in inches. Example.
Page 20 - Thus, it is 9 + 7+5 + 3 + 1 = 25, which shows that the whole spaces passed through in 5 seconds equal the square of 5. The momentum, or force, of a body falling through the atmosphere is the mass or weight, multiplied by the square root of the height it has fallen through, multiplied by 8-021. Suppose a weight of 10 tons to be raised 9 feet, and to drop thence suddenly on a bridge ; the momentum is 10 x (3x8-021) = 240-63 tons.

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