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12 feet ABCD adjacent angles allel altitude angles equal axis base multiplied bisect breadth called centre chains chord circle whose diameter circular sector circumference common cone consequently convex surface cube cylinder decimal dicular divide dodecagon draw entire surface equal altitudes equal Bk equal to half equivalent figure find the area frustum GEOMETRY half the arc half the product hence heptagon homologous sides hypothenuse included angle inscribed intersection length Let ABCD lower base measured by half Mensuration of Surfaces nonagon number of sides opposite angles outward angle parallelogram parallelopipedon pendicular pentagon perimeter perpen perpendicular plane prism PROBLEM quadrilateral radii radius rectangle regular polygon Required the area rhombus right angled triangle right angles Bk S-ABCDE segment slant height sphere square feet squares described straight line tangent THEOREM three sides trapezoid triangle ABC upper base viii
Page 48 - After remarking that the mathematician positively knows that the sum of the three angles of a triangle is equal to two right angles...
Page 58 - BD then A is said to have the same ratio to B, that C has to D ; or, the ratio of A to B is equal to the ratio of C to D.
Page 12 - America, but know that we are alive, that two and two make four, and that the sum of any two sides of a triangle is greater than the third side.
Page 118 - ... cylinder be cut by a plane parallel to the base, the section is a figure parallel and similar to the base. The one point a...
Page 112 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Page 162 - To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and then divide the product by two : the quotient will be the area (Bk.
Page 149 - This pulyedrun may be considered as formed of pyramids, each having for its vertex the centre of the sphere, and for its base one of the faces of the polyedron.