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" To find the sum of an arithmetical series : Multiply half the sum of the extremes by the number of terms. "
The Practical Arithmetic on the Inductive Plan: Including Oral and Written ... - Page 338
by William James Milne - 1877 - 391 pages
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Practical and Mental Arithmetic, on a New Plan, in which Mental Arithmetic ...

Roswell Chamberlain Smith - 1814 - 300 pages
...Hence, Шеп the flitretnes, ami the Number of Term«, ft given, loßnd the Sum of all the Terms;— Multiply half the sum of the extremes by the number of terms, and the product will be the answer. in. If the ertiemes be 3 and 373, and the number of terms 40, what...
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Arithmetick Theoretically and Practically Illustrated

B. M. Tyler - Arithmetic - 1827 - 308 pages
...series. RULE. Multiply the sum of the extremes by the number of terms, and divide the product by 2 ; or multiply half the sum of the extremes by the number of terms. 1 1. If the first term of an arithmetical series be 2, the last term 122, and the number of terms 29,...
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The Arithmetical Manual

Samuel Read Hall - Arithmetic - 1832 - 294 pages
...Ans. RULE 4. When the first, last and number of terms are given, to find the sum of all the terms or series, — Multiply half the sum of the extremes by the number of terms, and the product will be the answer. GEOMETRICAL PROGRESSION. By Geometrical Progression is meant, a...
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The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ...

Zadock Thompson - Arithmetic - 1832 - 186 pages
...IV. The first and last term, and the number of terms given to find the sum of the series. RULE. — Multiply half the sum of the extremes by the number of terms, and the product will be the sum of the series. 2. How many times does a common clock strike in 12 >ours?...
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The Youth's Assistant in Theorhetic [sic] and Practical Arithmetic: Designed ...

Zadock Thompson - Arithmetic - 1832 - 186 pages
...IV. The first and last term, and the number of terms given to find the sum of the series. ROLE. — Multiply half the sum 'of the extremes by the number of terms, and the product will be the sum of the series. 2. How many times does a common clock strike in 12 hours?...
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A New System of Arithmetic, on the Cancelling Plan: Embracing the Rules of ...

Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...When the first and last terms, and the number of terms are given, to find the sum of the series. RULE. Multiply half the sum of the extremes by the number of terms ; the product will be the sum of the series. 14. A man has 9 sons; the youngest is 8, the eldest 40...
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Practical and Mental Arithmetic ...

Roswell Chamberlain Smith - 1839 - 308 pages
...l*ence, JHien the Extremes, and the Number of Terms, cat given, to find the Sum of all the Terms ; — Multiply half the sum of the extremes by the number of terms, and the product will be the answer. 10. [f the extremes be 3 and 273, and the number of terms 40, what...
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A New System of Arithmetic: In which is Explained and Applied to Practical ...

Calvin Tracy - Arithmetic - 1840 - 316 pages
...35 cents, average price ; hence, 30x35 = $10.50, whole cost. We have the following rule : RULE. — Multiply half the sum of the extremes by the number of terms ; the product will be the answer. Z. Paid 4 cents for the first, and $1.21 for the last yard of a piece...
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Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...Hence, when the extremes, and the number of terms, are given, to find the sum of all the terms. — Multiply half the sum of the extremes by the number of terms, and the product will be the answer 22. If the extremes be 3 and 273, and the number of terms 40, «...
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Ruger's Arithmetick, with Questions and Answers: A New System of Arithmetick ...

William Ruger - Arithmetic - 1841 - 268 pages
...term, common difference, and the number of terms given, to find the sum of all the terms. RULE. — Multiply half the sum of the extremes by the number of terms, and the product will be the ansver or sum of all the terms. EXAMPLES. 1. A person bcught 16 yards of...
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