Through the points 1, 2, 3, &c. in the semi-circular arc, and in its developement, draw straight lines parallel to AE, and let the parallel lines through 1, 2, 3, in the arc A, B, C, meet FG, in p, q, r, &c. A popular and practical treatise on masonry and stone-cutting - Page 1by Peter Nicholson - 1828 - 111 pagesFull view - About this book
| Edward Shaw - Architecture - 1832 - 402 pages
...as in the preceding problem. Divide the semicircular arc, А В С, and the sectorial arc, AF, each into the same number of equal parts at the points 1, 2, 3, &c. From the points 1, 2 ,3 , &c. in the semi-circular arc, draw straight lines, 1 fc, 2 /, 3 m, &c. perpendicular... | |
| Edward Shaw - Architecture - 1832 - 244 pages
...and make AH equal to the developement of the arc ABC. Divide the arc ABC, and its developement, each into the same number of equal parts at the points 1, 2, 3. Through the points 1, 2, 3, &c. in the semi-circular arc and in its developement, draw straight lines... | |
| Edward Shaw - Architecture - 1836 - 438 pages
...and make AH equal to the developement of the arc ABC. Divide the arc ABC, and its developement, each into the same number of equal parts at the points, 1, 2, 3. Through the points 1, 2, 3, &c. in the semi-circular arc, and in its developement, draw straight lines... | |
| Joseph Gwilt - Architects - 1842 - 1114 pages
...straight lintt. Produce CB to F {fig. 455.), and make BF equal to BC. Join FD and FE. Divide DF and FE in the same proportion, or into the same number of equal parts. Let the divisions be numbered from D to F, and from F to E, and join every two corresponding points... | |
| Edward Shaw - Masonry - 1846 - 342 pages
...and make AH equal to the development of the arc ABС. Divide the arc ABС, and its development, each into the same number of equal parts at the points 1 , 2, 3. Through the points 1, 2, 3, &c., in the semicircular arc and in its development, draw straight lines... | |
| Edward Shaw - Architecture - 1852 - 426 pages
...H, and make AH equal to the development of the arc ABC. Divide the arc ABC and its development each into the same number of equal parts, at the points 1, 2, 3. Though the points 1, 2, 3, &c., in the semicircular arc, and in its development, draw straight lines... | |
| Spon E. & F.N., ltd - 1869 - 554 pages
...constructing at oßß'a'the development of the intrados: we draw the chords aß and o'jS', dividing them into the same number of equal parts, at the points 1, 2, 3, and so on; Г, 2', 3', and so on. We join any one point of division of a' ß' with a point of division... | |
| Edward Spon, Oliver Byrne, Ernest Spon, Francis N. Spon - Engineering - 1870 - 398 pages
...constructing at a 0 0'a' the development of the intrados : we draw the chords a /3 and o' I8', dividing them into the same number of equal parts, at the points 1, 2, 3, and so on ; 1', 2', 3', and so on. We join any one point of division of aß' with a point of division... | |
| Samuel Sloan - 1873 - 298 pages
...To do the same by another method. — Take the triangle С с d, and divide the sides С с and С d into the same number of equal parts at the points 1, 2, 3, etc. ; draw the lines 1 1, 2 2, 3 3, etc., and trace the curve so that these lines shall be tangent... | |
| Edward Wyndham Tarn - Curves, Plane - 1882 - 268 pages
...the rectangular hyperbola at the point /, and divide S l into any number of equal parts, and also AB' into the same number of equal parts at the points, 1, 2, &c. Draw the horizontals le, 2/, &c., cutting the rectangular hyperbola at e,f, &c., and draw the ordi... | |
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