 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...third terms to the same denomination, and reduce the second term to the lowest name mentioned in it. 3. Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...terms to the same denomination, and reduce the second term to the lowest naiae mentioned in it. 3. Multiply the second and third terms together, and divide their product by the first term, the quotient will be the answer to the question, in fue same denomination you left the second... | |
 | John Davidson, Robert Scott (writing master) - Arithmetic - 1818 - 190 pages
...write the greater as thefirst, and the other as the second proportional. The numbers being thus stated, multiply the second and third terms together, and divide their product by thefirst, the quotient will be the answer, in ihe same name in which the third term is9 when you arc... | |
 | Beriah Stevens - Arithmetic - 1822 - 436 pages
...extreme is the divisor. 3. Place the divisor on the left hand, and the other extreme on the right ; then multiply the second and third terms together, and divide their product by the first, ami the quotient gives the answer ; which is always of the same name with the middle term. When the... | |
 | Etienne Bézout - Mathematics - 1824 - 238 pages
...consequently, for performing the Simple Rule of Three Direct, a« explained in article (179), is as follows ; Multiply the second and third terms together and divide their product by the first ; the quotient will be the answer, or fourth term sought. -I he following examples will explain the... | |
 | John White - Arithmetic - 1826 - 128 pages
...first and third terms into the same denomination, and the second into the lowest name mentioned. 2. Multiply the second and third terms together, and divide their product by the first, and their quotient will be the answer, in the same denomination as that in which the second was left. •... | |
 | Martin Ruter - Arithmetic - 1828 - 180 pages
...Reduce, likewise, the first and second terms to the lowest denomination that either of them has. Then multiply the second and third terms together, and divide their product by the first term. The quotient thus obtained will be the answer. It will not be necessary to distinguish between... | |
 | William Slocomb - 1828 - 160 pages
...first and third terms to the same denomination, and the second to the lowest name mentioned in it. e 3. Multiply the second and third terms together, and divide their product by the first; the quotient will be the answer to the question, in the same denomination in which you left the second... | |
 | Roswell Chamberlain Smith - Arithmetic - 1829 - 284 pages
...it to the lowest denomination mentioned, by Reduction. VI. How do you proceed in the operation ? A. Multiply the second and third terms together, and divide their product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term.... | |
 | Roswell Chamberlain Smith - Arithmetic - 1830 - 286 pages
...it to the lowest denomination mentioned, by Reduction. VI. How do you proceed in the operation ? A. Multiply the second and third terms together, and divide their product by the first term ; the quotient will be the fourth term, or answer, in the same denomination with the third term.... | |
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Multiply the second and third terms together, and divide their product by the first, and the quotient is the answer in the same denomination to which the third is reduced. If any thing remains after division, reduce it to the next lowest denomination,... 
