| William Smyth - Algebra - 1830 - 280 pages
...required. Thus a 3 raised to the third power Conversely to extract the root of a simple quantity, we **divide the exponent of each letter by the index of the root.** Thus The utility of exponents of the kind, which we are here considering, consists principally in this,... | |
| Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 326 pages
...of a simple quantity to any degree whatever, we must (1.) extract the root of the coefficient, (2.) **divide the exponent of each letter by the index of the root.** Thus, 3 4 ^/64an3~c6 = 4a36c2; ^/l6«s6i2^ — 2a26*c. We see, according to this rule, that in order... | |
| Charles Davies - Algebra - 1835 - 378 pages
...Extraction of Roots. 199. To extract the n" root of a monomial, follow the rule given in Art. 182, viz. **divide the exponent of each letter by the index of the root.** For, the exponent of each letter in the result should be such, that multiplied by n, the index of the... | |
| Silas Totten - Algebra - 1836 - 360 pages
...Involve a * to the y power. ii t» vr a" ' = EXTRACTION OF ROOTS. RULE. (68.) Extract the root of the **coefficient, and divide the exponent of each letter by the index of the** required root. t. 2 1 Thus, the square root of a3 is or; and the cube root of a? is a* * = a* . EXAMPLES.... | |
| Charles Davies - Algebra - 1842 - 368 pages
...Hence, reciprocally, to extract any root of a monomial, 1st. Extract the root of the co-efficient. 2d. **Divide the exponent of each letter by the index of the root.** V64a 9 2rV=4a 3 Ac 3 ; Vl6a 8 i l V=2a 3 i 3 c. From this rule, we perceive, that in order that a monomial... | |
| Algebra - 1845 - 382 pages
...power, and unite the terms. Hence, to extract any root of a monomial, 1st. Extract the root of the **co-efficient and divide the exponent of each letter by the index of the root.** 2d. To the root of the coefficient annex each letter with its new exponent, and the result will be... | |
| Horatio Nelson Robinson - Algebra - 1846 - 276 pages
...following RULE. For the extraction of the roots of monomials. Extract the root of the numeral 'coefficients **and divide the exponent of each letter by the index of the root.** EXAMPLES. 1. What is the square root of 49a3x4? Ans. lax3. 2. What is the square root of 25c'663? Ans.5csb.... | |
| Horatio Nelson Robinson - Algebra - 1850 - 358 pages
...following RULE. For the extraction of the roots of monomials. Extract the root of the numeral coefficients **and divide the exponent of each letter by the index of the root.** EXAMPLES. 1. What is the square root of 49a?x t ? Ans. 7aaf. 2. What is the square root of 25e I0 6... | |
| Horatio Nelson Robinson - Algebra - 1850 - 256 pages
...factors. Thus the cube root of 8x2 is 2x. RULE . — Extract the root of the numeral coefficients, **and divide the exponent of each letter by the index of the root.** EXAMPLES. 1. What is the second root of 9o2aV ? , . Ans. 3aary. 2. What is the third root of 8aV ?... | |
| William Smyth - Algebra - 1855 - 370 pages
...power required. _2 Thus a raised to the third power Conversely, to extract the root of a monomial, we **divide the exponent of each letter by the index of the root.** Thus tfa-3 = a~3. The utility of exponents, of the kind which we are here considering, consists principally... | |
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