Elements of Geometry and Trigonometry |
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Page 4
Very considerable alterations have also been made in the manner of treating the subjects of Plane and Spherical Trigonometry . It has also been thought best to publish with the present edition a table of logarithms and logarithmic sines ...
Very considerable alterations have also been made in the manner of treating the subjects of Plane and Spherical Trigonometry . It has also been thought best to publish with the present edition a table of logarithms and logarithmic sines ...
Page 17
In like manner , since the angle F is equal to the angle C , the line FD will take the direction CA , and the point D will be found somewhere in the line CA. Hence , the point D , falling at the same time in the two straight lines BA ...
In like manner , since the angle F is equal to the angle C , the line FD will take the direction CA , and the point D will be found somewhere in the line CA. Hence , the point D , falling at the same time in the two straight lines BA ...
Page 20
In the same manner it may be shown that the angle E is equal to B , and the angle F to C : hence the two triangles are equal ( Prop . VI . Sch . ) . Scholium . It may be observed that the equal angles lie op- posite the equal sides ...
In the same manner it may be shown that the angle E is equal to B , and the angle F to C : hence the two triangles are equal ( Prop . VI . Sch . ) . Scholium . It may be observed that the equal angles lie op- posite the equal sides ...
Page 27
In the same manner it may be proved that OGA + GOC is equal to two right angles . Cor . 1. If OGB is a right angle , GOD will be a right angle also therefore , every straight line perpendicular to one of two parallels , is perpendicular ...
In the same manner it may be proved that OGA + GOC is equal to two right angles . Cor . 1. If OGB is a right angle , GOD will be a right angle also therefore , every straight line perpendicular to one of two parallels , is perpendicular ...
Page 29
in like manner , since AE , CB , are parallel , and AB cuts them , the alternate angles ABC , BAE , will be equal : hence the three angles of the triangle ABC make up the same sum as the three angles CAB , BAE , EAD ; hence , the sum of ...
in like manner , since AE , CB , are parallel , and AB cuts them , the alternate angles ABC , BAE , will be equal : hence the three angles of the triangle ABC make up the same sum as the three angles CAB , BAE , EAD ; hence , the sum of ...
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Common terms and phrases
ABCD adjacent altitude base become Book called centre chord circle circumference circumscribed common cone consequently construction contained corresponding cosine Cotang cylinder described diameter difference distance divided draw drawn equal equation equivalent evident expressed extremities fall figure follows formed formulas four frustum give given gles greater half hence homologous included inscribed intersection less likewise logarithm manner means measured meet middle multiplied opposite parallel parallelogram parallelopipedon pass perpendicular plane polygon prism PROBLEM Prop proportional PROPOSITION pyramid quantities radii radius ratio reason rectangle regular remaining right angles Scholium segment shown sides similar sine solid solid angle sphere spherical triangle square straight line Suppose surface taken tang tangent THEOREM third triangle triangle ABC vertex whole
Bibliographic information
| Title | Elements of Geometry and Trigonometry |
| Author | Adrien Marie Legendre |
| Editor | Charles Davies |
| Translated by | David Brewster |
| Edition | 4 |
| Publisher | A.S. Barnes and Company, 1834 |
| Original from | the University of California |
| Digitized | 14 Oct 2010 |
| Length | 359 pages |
| Export Citation | BiBTeX EndNote RefMan |