## Elements of Geometry and Trigonometry |

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Page 13

10. All right angles are equal to each other . 11. From one point to another only one straight line can be drawn . 12. Through the same point , only one straight line can be drawn which shall be parallel to a

10. All right angles are equal to each other . 11. From one point to another only one straight line can be drawn . 12. Through the same point , only one straight line can be drawn which shall be parallel to a

**given**line . 13. Page 21

If the angle C - B , then the side AB = AC ( Prop . XII . ) ; which is also contrary to the supposition . Therefore , when AB > AC , the angle C must be greater than B. PROPOSITION XIV . THEOREM . From a

If the angle C - B , then the side AB = AC ( Prop . XII . ) ; which is also contrary to the supposition . Therefore , when AB > AC , the angle C must be greater than B. PROPOSITION XIV . THEOREM . From a

**given**point , BOOK I. 21. Page 22

From a

From a

**given**point , without a straight line , only one perpendicu lar can be drawn to that line . Let A be the point , and DE the**given**line .. B E Let us suppose that we can draw two perpendiculars , AB , AC . Page 23

Let A be the

Let A be the

**given**point , DE the**given**line , AB the perpendicular , and AD , AC , AE , the oblique lines . Produce the perpendicular AB till BF is equal to AB , and draw FC , FD . First . The triangle BCF , is equal to the triangle ... Page 24

A Let AB be the

A Let AB be the

**given**straight line , C the oF 15.1 middle point , and ECF the perpendicular.qook onil First , Since AC = CB , the two oblique lines oup AD , DB , are equally distant from the perpen- dicular , and therefore equal ( Prop ...### What people are saying - Write a review

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### Common terms and phrases

ABCD adjacent altitude base become Book called centre chord circle circumference circumscribed common cone consequently construction contained corresponding cosine Cotang cylinder described diameter difference distance divided draw drawn equal equation equivalent evident expressed extremities fall figure follows formed formulas four frustum give given gles greater half hence homologous included inscribed intersection less likewise logarithm manner means measured meet middle multiplied opposite parallel parallelogram parallelopipedon pass perpendicular plane polygon prism PROBLEM Prop proportional PROPOSITION pyramid quantities radii radius ratio reason rectangle regular remaining right angles Scholium segment shown sides similar sine solid solid angle sphere spherical triangle square straight line Suppose surface taken tang tangent THEOREM third triangle triangle ABC vertex whole