These are the formulas which it was required to find. ་ The preceding demonstration may seem defective in point of generality, since, in the figure which we have followed, the arcs a and b, and even a+b, are supposed to be less than 90°. But first the demonstration is easily extended to the case in which a and b being less than 90°, their sum a+b is greater than 90°. Then the point F would fall on the prolongation of AC, and the only change required in the demonstration would be that of taking cos (a+b)= -CF; but as we should, at the same time, have CF'I'L-CK', it would still follow that cos (a+b)=CK'—I'L', or R cos (a+b)=cos a cos b―sin a sin b. And whatever be the values of the arcs a and b, it is easily, shown that the formulas are true: hence we may regard them as established for all arcs. We will repeat and number the formulas for the purpose of more convenient reference. sin a cos b+sin b cos a sin (a+b)= (1.). R sin a cos b-sin b cos a sin (ab) (2.). R XX. If, in the formulas of the preceding Article, we make b=a, the first and the third will give formulas which enable us to find the sine and cosine of the double arc, when we know the sine and cosine of the arc itself. Reciprocally, to divide a given arc a, into two equal parts, let us, in the same formulas, put a instead of a: we shall have 2 sin la cosa cosa sina R sin a= cos a 9 R ; Now, cos2a+sin2 a=R2, and cos2a-sin2a-R cos a, there results by adding and subtracting cos2 a=R2++R cos a, and sin2 a=R2-R cos a; whence sin a= √(√R2 —R cos a)=√2R2—2R cos.a. If we put 2a in the place of a, we shall have, sin a=√(R2R ̧ cós 2a)=√2R2—2R cos 2a. cos a= √(}R2+}R cos 2a)=¦√2R2 + 2R cos 2a. Making, in the two last formulas, a=45°, gives cos 2a=0, and sin 45°=√¥R2=R√; and also, cos 45°—√R2=R√}. Next, make a⇒22° 30′, which gives cos 2a=R✓, and we have sin 22° 30' R (√√, and cos 22° 30′ =R√({+}√}). XXI. If we multiply together formulas (1.) and (2.) Art. XIX. and substitute for cos2 a, R2-sin2 a, and for cos2 b, R2-sin2 b; we shall obtain, after reducing and dividing by R2, sin (a+b) sin (a—b)=sin2 a—sin2b=(sina+sin b) (sin a—sin b). or, sin (a-b) sin a-sin b:: sin a+ sin b: sin (a+b). XXII. The formulas of Art. XIX. furnish a great number of consequences; among which it will be enough to mention those of most frequent use. By adding and subtracting we obtain the four which follow, 2 cos (a—b)—cos (a+b)=sin a sin b. and which serve to change a product of several sines or cosines into linear sines or cosines, that is, into sines and cosines multiplied only by constant quantities. XXIII. If in these formulas we put a+b=p, a-b=q, which cot p tang p: formulas which are often employed in trigonometrical calculations for reducing two terms to a single one. XXIV. From the first four formulas of Art XXIII. and the first of Art. XX., dividing, and considering that we derive the following: sin a = sin p+sin q_sin † (p+q) cos § (p—q) __tang § (p+q) (p (p-q) tang (p—q) sin p+sin q_sin } (p+q) __tang (p+q) cos p+cos q cos (p+q) R cot a R sin p-sin q_cos (p+q)_cot (p+q) cos p+cos q = cos † (p+q) cos 1 (p−q) __ cot } (p+q) -cos psin (p+q)`sin } (p—q) tang cos q sin p+sin q 2sin(p+q) cos 1⁄2 (p—q) cos (p-q) (p—q) (p+q) sin (p+q) Formulas which are the expression of so many theorems. From the first, it follows that the sum of the sines of two arcs is to the difference of these sines, as the tangent of half the sum of the arcs is to the tangent of half their difference. T* XXV. In order likewise to develop some formulas relative to tangents, let us consider the expression tang (a+b)= cos (a+b) of sin (a+b) and cos (a+b), we shall find R (sin a cos b+sin b cos a) cos a cos b-sin b sin a R sin (a+b) tang (a+b)=: in which by substituting the values Now we have sin a= cos a tang a cos b tang b R : substitute these values, dividing all the terms by cos a cos b; we shall have tang (a+b)= R2 (tang a+tang b) which is the value of the tangent of the sum of two arcs, expressed by the tangents of each of these arcs. For the tangent of their difference, we should in like manner find R2 (tang a-tang b) tang (ab)=R2+tang a tang b Suppose b=a; for the duplication of the arcs, we shall have the formula R2-tanga Suppose b=2a; for their triplication, we shall have the for mula tang 3a= R2 (tang a+tang 2 a) in which, substituting the tang 3 a= ; R2-tang a tang 2 a XXVI. Scholium. The radius R being entirely arbitrary, is generally taken equal to 1, in which case it does not appear in the trigonometrical formulas. For example the expression for the tangent of twice an arc when R=1, becomes, If we have an analytical formula calculated to the radius of 1, and wish to apply it to another circle in which the radius is R, we must multiply each term by such a power of R as will make all the terms homogenious: that is, so that each shall contain the same number of literal factors. CONSTRUCTION AND DESCRIPTION OF THE TABLES. XXVII. If the radius of a circle is taken equal to 1, and the lengths of the lines representing the sines, cosines, tangents, cotangents, &c. for every minute of the quadrant be calculated, and written in a table, this would be a table of natural sines, cosìnes, &c. XXVIII. If such a table were known, it would be easy to calculate a table of sines, &c. to any other radius; since, in different circles, the sines, cósines, &c. of arcs containing the same number of degrees, are to each other as their radii. XXIX. If the trigonometrical lines themselves were used, it would be necessary, in the calculations, to perform the operations of multiplication and division. To avoid so tedious a method of calculation, we use the logarithms of the sines, cosines, &c.; so that the tables in common use show the values of the logarithms of the sines, cosines, tangents, cotangents, &c. for each degree and minute of the quadrant, calculated to a given radius. This radius is 10,000,000,000, and consequently its logarithm is 10. XXX. Let us glance for a moment at one of the methods of calculating a table of natural sines. The radius of a circle being 1, the circumference is known to be 3.14159265358979. This being divided successively, by 180 and 60, or at once by 10800, gives .0002908882086657, for the arc of 1 minute. Of so small an arc the sine, chord, and arc, differ almost imperceptibly from the ratio of equality; so that the first ten of the preceding figures, that is, .0002908882 may be regarded as the sine of 1'; and in fact the sine given in the tables which run to seven places of figures is .0002909. By Art. XVI. we have for any arc, cos=√(1--sin). This theorem gives, in the present case, cos 1'=.9999999577. Then by Art. XXII. we shall have 2 cos l'x sin 1'-sin 0'sin 2'=.0005817764 2 cos 1'x sin 3'-sin 2'-sin 4'=.0011635526 &c. &c. Thus may the work be continued to any extent, the whole difficulty consisting in the multiplication of each successivé result by the quantity 2 cos 1'=1.9999999154. |