The product of two binomials having a common term equals the square of the common term, plus the algebraic sum of the unlike terms multiplied by the common term, plus the algebraic product of the unlike terms. Complete School Algebra - Page 103by Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - 1919 - 507 pagesFull view - About this book
| Edward Brooks - Algebra - 1888 - 190 pages
...(a™ -6"). . Ans. a?m - b2". 9. Expand (a2™ + 63")(a2"> — 63"). ^Ins. a4™ — 6**. THEOREM IV. **The product of two binomials having a common term...of the common term, plus the algebraic sum of the** other two terms into the common term, and the product of the unlike terms. OPERATION. Let x + a and... | |
| David Martin Sensenig - Algebra - 1889 - 388 pages
...like term ; and the third term is the algebraic product of the unlike terms. Therefore, Prin. 40. — **The product of two binomials having a common term equals the square of the common term,** and the algebraic sum of the unlike terms times the common term, and the algebraic product of the unlike... | |
| David Martin Sensenig - Algebra - 1890 - 556 pages
...algebraic product of the unlike terms (+ ax + 6), (ox — S), (— о x — Ъ). Therefore, Prin. 2. — **The product of two binomials having a common term equals the square of the common term** and the algebraic sum of the unlike terms into the common term, and the algebraic product of the unlike... | |
| George Washington Hull - Algebra - 1895 - 360 pages
...9. (a - Sx) (a + 8ж). 19. (a"2 - 6™2) (a"2 + 6"2). 10. (3z - 7) (Зж + 7). 20. ( PRINCIPLE IV. **The product of two binomials having a common term...of the common term, plus the algebraic sum of the** other two terms into the common term, and the product of the unlike terms. Thus, by multiplication,... | |
| Edward Brooks - Algebra - 1901 - 248 pages
...+ 6n) (a" -?'"). 14. (a'na;'ri) (a'--ta;'") 15. (a'-'-c"*1) (a"-' 16. an + nc" + na"' + THEOREM IV. **The product of two binomials having a common term equals the square of** tlie common term, plus tlie algebraic sum of the other two terms into the common tern, and tlie product... | |
| John Henry Tanner - Algebra - 1904 - 396 pages
...general, (z + a) (x + b) = я? + (a + b)x + ob ; ie the product of two binomials having a term in common **equals the square of the common term, plus the algebraic...unlike terms multiplied by the common term, plus the** product of the unlike terms. EXERCISES Without actually performing the following multiplications, write... | |
| John William Hopkins - 1904 - 274 pages
...x + 24 ж2 + 11 x + 24 Multiply (x - 8) by (x - 3). ж - 8 x - 3 ж2- 8ж - Зж + 24 ^ - 11 x + 24 **The product of two binomials having a common term equals the square of the common term,** the algebraic sum of the other two terms into the common term, and the product of the other two terms.... | |
| Arthur William Potter - Algebra - 1904 - 182 pages
...having a common term the first term of the product is the square of the common term; the second term is **the algebraic sum of the unlike terms multiplied by the common term;** the third term is the product of the unlike terms. Write the product of the following quantities :... | |
| George Washington Hull - Algebra - 1904 - 172 pages
...PRINCIPLE IV. The product of two binomials having a common term is equal to the square of the common term, **the algebraic sum of the unlike terms multiplied by the common term,** and the algebraic product of the unlike terms. Thus, by multiplication, a + b a + с a? + ba + ca +... | |
| John Charles Stone, James Franklin Millis - Algebra - 1905 - 792 pages
...(a; + J) = жг + ax + &E + ai. Adding like terms, this becomes я? + (a + b)x + ab. Hence, That is, **the product of two binomials having a common term equals the square of the common term, plus the** product of the common term and the sum of the otlwr terms, plus the product of the other terms. EXAMPLE... | |
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