Walkingame's Arithmetic Simplified ...

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Page 117 - To reduce a mixed number to an improper fraction. RULE. Multiply the whole number by the denominator of the fraction, and to the product add the numerator for a new numerator, and place it over the denominator. 1. Reduce 127T^ to an improper fraction.
Page 118 - To reduce fractions of different denominators to equivalent fractions, having a common denominator. RULE. — Multiply each numerator into all the denominators except its own for the new numerators ; and multiply all the denominators together for a common denominator.
Page 139 - The top of a castle from the ground is 45 yards high, and is surrounded with a ditch 60 yards broad ; what length must a ladder be to reach from the outside of the ditch to the top of the castle ? Ans.
Page 56 - All small names are brought into great by dividing with so many of the less as make one of the greater.
Page 107 - II. When it is required to find how many of the last sort of coin, weight or measure, mentioned in the question,, are equal to a gjveu quantity of the first.
Page 101 - EXAMPLES. 1. A schoolmaster, being asked how many scholars he had, said, If I had as many, half as many, and one quarter as many more, I should have 264: how many had he?
Page 117 - To reduce a compound fraction to a single one. RULE. Multiply all the numerators together for a new numerator, and all the denominators for a new denominator, then reduce the new fraction to its lowest term by Case I.
Page 142 - To extract the Square Root of a Vulgar Fraction. RULE, Reduce the fraction to its lowest terms, then extract the square root of the numerator for a new numerator, and the square root of the denominator for a new denominator.
Page 142 - There is a cellar dug that is 12 feet every way, in length, breadth, and depth; how many solid feet of earth were taken out of it? Ans. 1728. 42. How many bricks 9 inches long and 4 inches wide, will pave a yard that is 20 feet square?
Page 72 - Multiply the first and second terms together, and divide the product by the third ; the quotient will be the answer in the same denomination as the middle term was reduced into.

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