| John Keill - Logarithms - 1723 - 444 pages
...is * equal to the whole Angle FBC. And *^.. ^ fince the two Sides AB, BD, are equal to the two Sides **FB, BC, each to each, and the Angle DBA equal to the Angle FBC;** the Bafe AD will be ft equal to the Bafe FC, and the Triangle ABD equal to the Triangle FBC: But the... | |
| Euclid, John Keill - Geometry - 1733 - 444 pages
...is * equal to the whole Angle FB C. And* Ax. fince the two Sides AB, BD, are equal to the two Sides **FB, BC, each to each, and the Angle DBA equal to the Angle FBC;** the Bafe AD will be ft 4 equaj to the Bafe FC, and the Triangle ABD equal to the Triangle FBC: But... | |
| Robert Simson - Trigonometry - 1762 - 488 pages
...the fame reafon CF is equal to FD. and becaufe AD is equal to BC, and AF to FB, the two fides FA, AD **are equal to the two FB, BC, each to each ; and the** bafe DF was proved equal to the bafe FC ; therefore the angle FAD is eeq'.ial d to the angle FBC. agam,... | |
| Robert Simson - Trigonometry - 1775 - 534 pages
...ABC, and the whole angle DBA is eq'ualc to the whole FBC ; and becaufe the two fides AB, BD c •- Ax. **are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC ; therefore the** bafe AD is eqwlftothe bafe FC, and the triangle ABD to the triangle f 4- i. IBC : Now the parallelogram... | |
| Euclid - 1781 - 552 pages
...fame reafon, CF is equal to FD : And becaufe AI? is equal to BC, and AF to FB, the two fides FA, AD **are equal to the two FB, BC, each to each ; and the** bafe DF was proved equal to the bafe FC ; therefore the angle FAD is equal d to the angle FBC : Again,... | |
| Euclid, John Playfair - Euclid's Elements - 1795 - 462 pages
...and the whole angle DBA is equal e to til whole FBC ; and becaufe the two fides AB, BD are equal tt **the two FB, BC, each to each, and the angle DBA equal** th the angle FBC ; therefore the bafe AD is equal f to the bafe Book I. FC, and the triangle \BD to... | |
| Alexander Ingram - Trigonometry - 1799 - 374 pages
...angle ARC, e s. Ax. and tne whole angle DBA is equal e to the whole FBC ; and becaufe the two fides **AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC** ; f 4. i. therefore the bafe AD is equal i to the bafe FC, and the triangle ABD to the triangle FBC... | |
| John Playfair, Euclid - Circle-squaring - 1804 - 468 pages
...each the angle ABC, the whole angle DBA will be equal e to the whole FBC ; and becaufe the two fides **AB, BD, are equal to the two FB, BC, each to each, and the angle DBA equal to** tho the angle FBC, therefors the bafe AD is equal f te the bafe Book I. FC, and the triangle ABD to... | |
| Robert Simson - Trigonometry - 1804 - 530 pages
...the fame reafon CF is equal to FD. and becaufe AD is equal to BC, and AF to FB, the two fides FA, AD **are equal to the two FB, BC, each to each; and the** bafe DF was proved equal to the bafe FC ; therefore the angle FAD is equal d to the angle FBC. again,... | |
| John Playfair - Euclid's Elements - 1806 - 320 pages
...of them being a right angle, add to each the angle ABC, and the whole H D angle DBA will be equalf **to the whole FBC ; and because the two sides AB, BD...DBA equal to the angle FBC, therefore the base AD is** equals to the base FC, and the triangle ABD to the triangle FBC. But the parallelogram BL is double11... | |
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