 BK, it is demonstrated that the parallelogram CL is equal to the square HC. Therefore the whole square BDEC is equal to the two squares GB, HC ; and the square BDEC is described upon the straight line BC, and the squares GB, HC upon BA, AC.  Elements of Geometry: With Notes - Page 185by John Radford Young - 1827 - 208 pagesFull view - About this book
 | Colin Macfarquhar, George Gleig - Encyclopedias and dictionaries - 1801 - 436 pages
...the triangle conftrueteci on the bafe of one ef the fquares, introduces an attiomt and fays, " hut the doubles of equals are equal to one another ; therefore the parallelogram is equal to the fquare." But if from this moi'e of exprtffion any шип conceive the axiom or univerial... | |
 | John Playfair, Euclid - Circle-squaring - 1804 - 468 pages
...triangle BFC, becaufe thefe alfo are upon the fame bale FB, and between the fame parallels FB, GC. Now the doubles of equals are equal '» to one another^ therefore the parallelogram h 6. Ax. JBL is equal to the fquare GB : And, in the fame manner, by joining AE, BK, it is demonftrated... | |
 | Robert Simson - Trigonometry - 1806 - 546 pages
...between the same parallels FB, GC. But the doubles of equals• are equal h to one another : h 6. A* therefore the parallelogram BL is equal to the square GB : and in the same manner, by joining A I'.. BK, it is demonstrated that the parallelogram CL is equal to the square HC : therefore the whole... | |
 | Euclid - Geometry - 1810 - 554 pages
...between the same parallels FB, GO. But the doubles of equals are equal h to one another : h 6. Ax. therefore the parallelogram BL is equal to the square...manner, by joining AE, BK, it is demonstrated that tie parallelogram CL is equal to the square HC : therefore the • whole square BDEC is equal to the... | |
 | Euclides - 1816 - 588 pages
...the same base FB, and between the same parallels FB, GC. But the doubles of equals are equal h to Al% one another: Therefore the parallelogram BL is equal...square GB : And, in the same manner, by joining AE, BK, 'tis demonstrated, that the parallelogram CL is equal to the square HC; Therefore the whole square... | |
 | Peter Nicholson - Mathematics - 1825 - 1046 pages
...the same base FB, and between the sama parallels FB, GC. But the doubles of equals are equal (6. Ax.} to one another : Therefore the parallelogram BL is. equal to the square GB : And, in (he same manner by joining AE, BK, it ¡s demonstrated that (he parallelogram CL is equal to the square... | |
 | Euclid, John Playfair - Euclid's Elements - 1826 - 326 pages
...between the same parallels FB, GC, Now the doubles of equals are equal (6. Ax.) to one another; then-lore the parallelogram BL, is equal to the square GB : And in the same manner, by joining AE,BK, it is demonstrated that the parallelogram CL is equal to the square 1 1C. Therefore, the whole... | |
 | Euclides - 1826 - 226 pages
...they have the same base FB, and are between the same parallels FB, GC. But things which are double of equals are equal to one another; therefore the parallelogram BL is equal to the square BG. In like manner AE, вк, being joined, the parallelogram CL may be also shown to be equal to the... | |
 | Euclid - 1826 - 234 pages
...they have the same base FB, and are between the same parallels FB, GC. But things which are double of equals are equal to one another ; therefore the parallelogram BL is equal to the square BG. In like manner AE, вк, being joined, the parallelogram CL may be also shown to be equal to the... | |
 | Thomas Perronet Thompson - Euclid's Elements - 1833 - 168 pages
...are on the same base FB, and between the same parallels FB, GC ; but the doubles of equal things arej equal to one another; therefore the parallelogram BL is equal to the square BAGF. In the same way may be shown, that the parallelogram CL is equal to the square ACKH. Therefore,... | |
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