 1 — cos a 1 + cos a 1 + cos a * 1 + cos a sin a 16. If a numerical value of any function of a is given, all the other functions of a and of a/2 can be found geometrically from Ex. 14. Thus, if sin a = 4/5 is given, lay off OP = 5, BP = 4 ; then 07?...  Trigonometry - Page 87by Alfred Monroe Kenyon, Louis Ingold - 1913 - 256 pagesFull view - About this book
 | Ferdinand Rudolph Hassler - Trigonometry - 1826 - 212 pages
...-- = -- _. _ — __ (l + cosa)* (1 -cosa)* (1 — cos2 a). sine Or, multiplying in the same way by (1 + cos a)* (1 - cos a)* (1 + cos a)* (1 - cos" a)« sin a 7 tan à a = 1 + cos a 1 + cos a 1 + cos a By the division of No. 2 of this series by No. 4, we obtain... | |
 | George Albert Wentworth - Trigonometry - 1896 - 394 pages
...cos a = 1 — 2 sin2 | a = 2 cos2 i a— 1. .,_,, 1-cosa .-. sm'фa— 2 1 + cosa 2 3 sin2 ia cos2 ia 1 — cos a 1 + cos a /1 — cos a . \ 1 + cos a .,, , 630° .-. 34- radians = log 3.14159 = 0.49715 , .. 180° 1 radian = я я 630° 3.14159 log 630... | |
 | Alfred Monroe Kenyon, Louis Ingold - Plane trigonometry - 1919 - 306 pages
...+ cosa) tan fa/21 = 's(noe _ Vl — cos2 a _ /1.— cosa _ 1 — 1 + cos a 1 + cos a ' 1 + cos a si sin a 16. If a numerical value of any function of...sin a = 4/5 is given, lay off OP= 5, BP = 4 ; then OB = Vo^ - 42= 3. Hence, CB = 8, ВЛ = 2 ; and CP = V OB2 + Ш* = V82 + 42= V80. It follows that sin... | |
 | Alfred Monroe Kenyon, Louis Ingold - Plane trigonometry - 1921 - 304 pages
...sin (a/2) = r sin a =^ j-cosa . rл/2(l + cosa) ' + cos a V2(l + cosa) . (ffin\ mil ц vj — uuo- u, /1 — COS a 1 — COS a 1 + cos a 1 + cos a * 1 + cos a sin a 16. If 'a numerical value of any function of a is given, all the other functions... | |
 | I.M. Gelfand, Mark Saul - Mathematics - 2001 - 244 pages
...+ cos a — -j= ± rnc ( a \ \ 21 -U V 1 1 + cos a 2 sinf'M sin^ 2 j /I — cos a t V 2 , we write 1 — cos a 1 + cos a 1 — cos a 1 + COS a 1 — cos a 1 — cos a 1 + cos a In the next section, we will see two formulas for tan (a/2) that... | |
 | Pierangelo Andreini - Technology & Engineering - 2002 - 2342 pages
...J"\ - sen a sen a 1 - cos a tg 1/2 a = ctg 1/2 a = 1 + cos a sen a 1 - cos a sen a 1 + cos a sen a 1 - cos a 1 + cos a 1 + cos a 1 - cos a l-tg2ot ctga-tga' 2 Ctg a ctg3a-3 ctg a , j ig a-ig"a . „ _ cig^aj cigt tgj"~ 1-3 tg2« ' Ctg3" 3ctg2a-1... | |
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