 | Charles Hutton - Mathematics - 1811 - 494 pages
...similar cones AST, QMI, as * E 2 52 MENSURATION or SOLIDS. take double the height of -the segment ; then multiply the remainder by the square of the height, and the product by the decimal -5436, for the content. RULE II. To 3 times the square of the radius of the segment's base,... | |
 | Charles Hutton - Mathematics - 1812 - 620 pages
...$ TI = £. ad* ; and by the similar cones ABI, <IMI, u take double the height of the segment : then multiply the remainder by the square of the height, and the product by the decimal -5236, for the content. RULE II. To 3 times the square of the radius of the segment's base,... | |
 | Charles Hutton - Astronomy - 1815 - 686 pages
...'5236. Or, 2dly, From 3 times the diameter of the sphere, subtract twice the height of the frustum ; multiply the remainder by the square of the height, and the product by '5236. That is, in symbols, the solid content is either = -5236« x (Зг3 + oa), or = -5236a* х (3d... | |
 | William Nicholson - Natural history - 1821 - 384 pages
...52J6. Or, 2dly, From three times the diameter of thesphere. subtract twice the height of the frustrum; multiply the remainder by the square of the height, and the product by .5236. SEGUIERIA, in botany, so named in honour of Jean Francois Seguier, u genus of the Polyandria... | |
 | William Nicholson - Natural history - 1821 - 382 pages
....52J6. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum; multiply the remainder by the square of the height, and the product by .5236. SEGUIER1A, in botany, so named in honour of Jean Francois Seguier, a genus of the Polyandna... | |
 | Charles Hutton - Mathematics - 1822 - 616 pages
...£ad3 X in =Jiad3 ; and by the similar cones ABI, «MI, is n double the height of the segment : then multiply the remainder by the square of the height, and the product by the decimal -5236, for the content. RULE II. To 3 times the square of the radius of the segment's base,... | |
 | James Mitchell - Mathematics - 1823 - 666 pages
...Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum ; multiply the remainder by the square of the height, and the product by -5236. That is, in symbols, the solid content is either = (3d— 2o) ; where a is the altitude of the... | |
 | Edinburgh encyclopaedia - 1830 - 856 pages
...segment. RULE. From three times the diameter of the sphere, take twice the height of the segment, then multiply the remainder by the square of the height, and the product by the decimal .5236 for the content. This rule may be derived from Ex. S. Art. l6l. FLUXIONS ; or it... | |
 | Thomas Spofford - Almanacs, American - 1835 - 84 pages
...decimal .5236. RULE 2. — From three tim^s the diameter of the Globe, subtract twice the heightof the Segment ; multiply the remainder by the square of the height, and the product by .5236. NOTE. — The surface or nrea of the Frustum is thus found :— as the diameter of the Globe... | |
 | B[enjamin] Franklin Callender - Measurement - 1836 - 226 pages
...the Segment of a Spheroid. From the product of three times the axis, subtract twice the height of the segment ; multiply the remainder -by the square of the height, and the product by .5236. Then, as the square of the axis is to the square of the revolving diameter, so is the last product... | |
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From three times the diameter of the sphere, take double the height of the segment ; then multiply the remainder by the square of the height, and the product by the decimal .5236... 
