The product of two binomials having a common term equals the square of the common term plus the product of the common term by the sum of the other terms, plus the product of the other terms. Elementary Algebra - Page 83by Elmer Adelbert Lyman, Albertus Darnell - 1917 - 503 pagesFull view - About this book
| Edward Brooks - Algebra - 1888 - 190 pages
...(a™ -6"). . Ans. a?m - b2". 9. Expand (a2™ + 63")(a2"> — 63"). ^Ins. a4™ — 6**. THEOREM IV. The product of two binomials having a common term equals the square of the common term, plus the algebraic sum of the other two terms into the common term, and the product of the unlike terms. OPERATION.... | |
| David Martin Sensenig - Algebra - 1889 - 388 pages
...like term ; and the third term is the algebraic product of the unlike terms. Therefore, Prin. 40. — The product of two binomials having a common term equals the square of the common term, and the algebraic sum of the unlike terms times the common term, and the algebraic product of the unlike... | |
| David Martin Sensenig - Algebra - 1890 - 556 pages
...algebraic product of the unlike terms (+ ax + 6), (ox — S), (— о x — Ъ). Therefore, Prin. 2. — The product of two binomials having a common term equals the square of the common term and the algebraic sum of the unlike terms into the common term, and the algebraic product of the unlike... | |
| Scoby McCurdy - Algebra - 1907 - 264 pages
...14. ж8 — ж-2. . Page 14, § 47. 1. The product of two binomials having a common term is equal to the square of the common term, plus the product of the common term and the sum of the second terms, plus the product oj the second terms. 2. x2 + (a + b) x +ab. 3. ж2... | |
| George Washington Hull - Algebra - 1895 - 358 pages
...9. (a - Sx) (a + 8ж). 19. (a"2 - 6™2) (a"2 + 6"2). 10. (3z - 7) (Зж + 7). 20. ( PRINCIPLE IV. The product of two binomials having a common term equals the square of the common term, plus the algebraic sum of the other two terms into the common term, and the product of the unlike terms. Thus,... | |
| Edward Brooks - Algebra - 1901 - 248 pages
...+ 6n) (a" -?'"). 14. (a'na;'ri) (a'--ta;'") 15. (a'-'-c"*1) (a"-' 16. an + nc" + na"' + THEOREM IV. The product of two binomials having a common term equals the square of tlie common term, plus tlie algebraic sum of the other two terms into the common tern, and tlie product... | |
| John William Hopkins - 1904 - 276 pages
...x + 24 ж2 + 11 x + 24 Multiply (x - 8) by (x - 3). ж - 8 x - 3 ж2- 8ж - Зж + 24 ^ - 11 x + 24 The product of two binomials having a common term equals the square of the common term, the algebraic sum of the other two terms into the common term, and the product of the other two terms.... | |
| John Charles Stone, James Franklin Millis - Algebra - 1905 - 776 pages
...(a; + J) = жг + ax + &E + ai. Adding like terms, this becomes я? + (a + b)x + ab. Hence, That is, the product of two binomials having a common term...the common term, plus the product of the common term and the sum of the otlwr terms, plus the product of the other terms. EXAMPLE 1. (x+2)(x+S)= Check.... | |
| Joseph Victor Collins - Algebra - 1908 - 442 pages
...X* + (a + b)x + ab. »' + (« + b)x + ab Changing this formula into a theorem, we have THEOREM IV. The product of two binomials having a common term equals the square of the commom term, plus the algebraic sum of the other terms times the common term, plus the algebraic product... | |
| Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - Algebra - 1910 - 374 pages
...gives the formula (x + a)(x + b) = x' + (a + b)x+ab. This may be expressed in words as follows : IV. The product of two binomials having a common term equals the square of the common term, plus the algebraic sum of the unlike terms multiplied by the common term, plus the algebraic product of the... | |
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