| George Washington Hull - Geometry - 1807 - 408 pages
...231. The area of a triangle is equal to one half the product of its base and altitude. Given — ABC **a triangle having its altitude equal to a and its base equal to** 6. To Prove— Area ABC= } ax b. Dem. — Construct the parallelogram ABEC. Now, &ABC= \EHASEC. §220... | |
| Adrien Marie Legendre - Geometry - 1871 - 492 pages
...other as their altitudes. K f* i A ~ D PROPOSITION VI. THEOREM. The area of a triangle is equal to half **the product of its base and altitude. Let ABC be a triangle,** BG its base, and AD its altitude : then will the area of the triangle be equal to $BC x AD. For, from... | |
| Edward Olney - Geometry - 1872 - 566 pages
...parallelogram is equivalent to a rectangle of the same base and altitude (313). 323. COB. 3. — The **area of a triangle is equal to one-half the product of its base and altitude;** fora triangle is one-half of a parallelogram of the same base and altitude (3 14). 324. COB. 4. —... | |
| Edward Olney - Geometry - 1872 - 472 pages
...parallelogram is equivalent to a rectangle of the same base and altitude (313). 323. COR. 3. — The **area of a triangle is equal to one.half the product of its base and altitude** ; for a triangle is one.half of a parallelogram of the same base and altitude (3 14). 32Ф. COR. 4.... | |
| Charles Davies - Geometry - 1872 - 464 pages
...to each other as their altitudes. PROPOSITION VI. THEOREM. The area of a triangle is equal to half **the product of its base and altitude. Let ABC be a triangle,** BC its base, and AD is Mtitude : then will the area of the triangle be equal to {BC x AI>. For, from... | |
| William Chauvenet - Geometry - 1875 - 390 pages
...their bases by their altitudes. PROPOSITION V.— THEOREM. 13. The area of a triangle is equal to half **the product of its base and altitude. Let ABC be a triangle,** k the numerical measure of its base BC, h that of its altitude AD; / and S its area ; then, 8 = J k... | |
| Joseph Ficklin - Arithmetic - 1881 - 406 pages
...altitude 6 ft. 9 x fi SOLUTION. — — = 27 ; hence, the area is 27 sq. ft. a EXPLANATION. — The **area of a triangle is equal to one-half the product of its base and altitude.** FORMULA : Area of triangle = \ (Base x Altitude). 2. What is the area of a triangle whose base is 50... | |
| James Morton - Circle-squaring - 1881 - 240 pages
...circumf. into three equal parts ; draw the chords AC, AB, C B. The area of this triangle is equal to half **the product of its base and altitude. Let ABC be a triangle,** and BD perpendicular to the base ; then will its area be equal to one-half of ACxBD. For draw CE parallel... | |
| Edward Olney - Geometry - 1883 - 352 pages
...parallelogram is equivalent to a rectangle of the same base and altitude (332). 347. COROLLARY 3.—The **area of a tri-angle is equal to one-half the product of its base and altitude;** for a triangle is one-half of a parallelogram of the same base and altitude (333). 348. COROLLARY 4.—Parallelograms... | |
| Alfred Hix Welsh - Geometry - 1883 - 326 pages
...stones, of rectangular form, 2 ft. 3 in. by 10 in., will be required to pave it? THEOREM VI. • The **area of a triangle is equal to one-half the product of its base** by its altitude. r- Let ABD be any triangle; then 7 will ABD = $ a b. ^/ For, draw DC parallel to AB,... | |
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