 | Euclides - 1864 - 262 pages
...AC is equal to the sum of the segments of the base, made by the perpendicular from the vertex A. 37. Let the sides AB, AC of any triangle ABC be produced,...angle BAC. For draw DE perpendicular on BC, also DF, DO perpendiculars on AB, AC produced, it necessary. Then DF may be proved equal to DG, and the squares... | |
 | Euclides - 1864 - 448 pages
...AC is equal to the sum of the segments of the base, made by the perpendicular from the vertex A. 37. Let the sides AB, AC of any triangle ABC be produced, the «• tenor angles bisected by two lines which meet in D, and let AD be joined, then AD bisects the... | |
 | Robert Potts - 1865 - 528 pages
...of the base, made by the perpendicular from the vertex A. 41. Let the sides AB, AC of any trianple ABC be produced, the exterior angles bisected by two...Then DF may be proved equal to DG, and the squares on DF. DA are equal to the squares on DG, GA, of which the square on FD is equal to the square on DG... | |
 | Robert Potts - 1868 - 434 pages
...is equal to the sum of the segments of the base, made by the perpendicular from the vertex A. tenor angles bisected by two lines which meet in D, and let AD be joined, then AD bisects the angle BAG. For draw DE perpendicular on BC. also DF, DG perpendiculars on AB, AC produced, if necessary.... | |
 | Robert Potts - Geometry - 1876 - 446 pages
...AC is equal to the sum of the segments of the base, made by the perpendicular from the vertex A, 37. Let the sides AB, AC of any triangle ABC be produced, the exUrior angles bisected by two lines which meet in D, and let AD be joined, then A 1) bisects the angle... | |
 | Joseph Hughes - Education - 1883 - 568 pages
...intersection of the bisecting lines to the opposite angle of the triangle will bisect that angle. В Let the sides AB, AC of any triangle ABC be produced,...bisected by two lines which meet in D, and let AD Ьг joined, then AD bisects the angle ВАС. For draw DE perpendicular on BC, also DF, DG, perps.... | |
 | Education - 1883 - 654 pages
...intersection of the bisecting lines to the opposite angle of the triangle will bisect that angle. В Let the sides AB, AC of any triangle ABC be produced, the exterior angles bisected by tw о lines which meet in D, and let AD be joined, then AD bisects the angle ВАС. For draw DE perpendicular... | |
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... angle ACB double of the angle ABC, and let the perpendicular AD be drawn to the base BC. Take DE equal to DC and join AE. Then AE may be proved to be equal to EB. If ACB be an obtuse angle, then AC is equal to the sum of the segments of the base,... 