| Silvestre François Lacroix - Algebra - 1818 - 422 pages
...tens plus the unite, or 2 a + b ; this multiplied by 7 or 6, reproduces 609 = 2 ab + 62, or double the product of the tens by the units, plus the square of the units. This being subtracted leaves no remainder, and the operation shows, that 47 is the square root of 2209.... | |
| Adrien Marie Legendre - Geometry - 1819 - 574 pages
...the tens plus the units, or 2 a + b ; this multiplied by 7 or b, reproduces 609 = 2a6 + 6s, or double the product of the tens by the units, plus the square of the units. This being subtracted leaves no remainder, and the operation •hows, that 47 is the square root of... | |
| Bézout - Arithmetic - 1825 - 258 pages
...add these products, and we have, for the square, the number 2916, which, as we see, is composed of the square of the tens, plus twice the product of...the tens by the units, plus the square of the units of the number 54. 134. What we have, observed being an immediate consequence of the rules of multiplication,... | |
| William Smyth - Algebra - 1830 - 278 pages
...62=2209. Thus the square of a number, consisting of units and tens, is composed of three parts, viz. the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. Thus in 2209, the square of 47, we have The... | |
| Zadock Thompson - Arithmetic - 1832 - 186 pages
...appears that the square of a number consisting of tens and units is made up of the square of the units, plus twice the product of the tens, by the units, plus the square of the tens. See this exhibited in figure F. As 10X 10=100, the square of the tens can never make a part of... | |
| Zadock Thompson - Arithmetic - 1832 - 186 pages
...appears that the square of a number consisting of tens and units is made up of the square of the units, plus twice the product of the tens, by the units, plus the square of the tens. See this exhibited in figure F. As 10X 10=100, the square of the tens cau never make a part of... | |
| Charles Davies - Algebra - 1835 - 378 pages
...60+4=64. Now, if we represent the tens by a and the units by b, we shall have a+i = 64 and (a+i)3= (64)3 Which proves that the square of a number composed...the tens by the units, plus the square of the units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by annexing to each figure a cipher, we shall... | |
| Silas Totten - Algebra - 1836 - 320 pages
...the units, we shall have, for the square of a + b, a3 + 2ab + b ; that is, the square of the tens, twice the product of the tens by the units, plus the square of the units. Let a = 8, and 6 = 5: then, since a represents the tens, and b the units, a + b becomes 80 + 5 = 85... | |
| Algebra - 1838 - 372 pages
...the tens by a and the units by b, we shall have a+i = 64 and (a+i)3=(64)", or . . aa+2a*+i3 =4096. Which proves that the square of a number composed...the tens by the units, plus the square of the units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by annexing to each figure a cipher, we shall... | |
| Bourdon (M., Louis Pierre Marie) - Algebra - 1839 - 368 pages
...to which we bring down the two next figures 84. The result of this operation 1184, contains tzeice the product of the tens by the units plus the square of the units. But since tens multi. plied by units cannot give a product of a less name than tens, it follows that... | |
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