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" Divide the greater number by the less, and the divisor by the remainder, and so on, until there is no remainder ; the last divisor will be the greatest common divisor. "
Children's Arithmetic by Grades: Essential elements. Fourth book, fifth year - Page 63
by William Estabrook Chancellor - 1901 - 144 pages
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An Elementary and Practical Arithmetic

James B. Dodd - Arithmetic - 1850 - 276 pages
...into the greater, and the remainder into the divisor, and the last remainder into the last divisor, and so on, until there is no remainder. The last divisor will be the common measure required. 2. For three or more numbers, — divide the least number into each of the...
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High School Arithemtic: Containing the Elementary and the Higher Principles ...

James B. Dodd - Arithmetic - 1852 - 410 pages
...others, and take the remainders and divisor for a new set of numbers, with which proceed as before, and so on, until there is no remainder. The last divisor will be the common measure required. EXAMPLE. To find the greatest common measure of 1 35 and 720. 135)720(6 675...
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High School Arithmetic

James B. Dodd - 1853 - 398 pages
...others, and take the remainders and divisor for a new set of numbers, with which proceed as before, and so on, until there is no remainder. The last divisor will be the common measure required. EXAMPLE. To find the greatest common measure of 135 and 720. 135)720(5 675...
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The science of arithmetic, by J. Cornwell and J.G. Fitch

James Cornwell - 1855 - 382 pages
...divide it by the first remainder. Afterwards bring down the second divisor and divide it by the second remainder, and so on until there is no remainder. The last divisor is the greatest common measure of the two original numbers. If the last divisor be 1, the numbers have...
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Arithmetic for High Schools: Containing the Elementary and the Higher ...

James B. Dodd - Arithmetic - 1859 - 368 pages
...others. 2. Take the divisor and remainders for a new set of numbers, with which proceed as before ; and so on, until there is no remainder. The last divisor will be the greatest common measure of the given numbers. Thus, to find the greatest common measure of 390, 930,...
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First book of arithmetic for the use of schools. [With] Key. High-school ed ...

Ireland commissioners of nat. educ - 1865 - 184 pages
...24, 30. To find the GC М. of two numbers. RULS. — Divide the greater number by the less; then tht divisor by the remainder ; next the last divisor by...so on until there is no remainder. The last divisor is the GC М. EXAMPLE.— What is the GCM of 1825 and 2555 1 1825)2555(1 1825 "730)1825(2 1460 365)730(2...
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Arithmetic for school and college use. With a chapter on the metric system

Thomas Percy Hudson - Arithmetic - 1866 - 268 pages
...measure of two given numbers. RULE : Divide the greater by the less, then the preceding divisor by the remainder, and so on, until there is no remainder. The last divisor will be the greatest common measure required. EXAMPLE. — To find the greatest common measure of 532 and 1274....
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Arithmetic

Charles Elsee - Arithmetic - 1866 - 300 pages
...measure of two numbers. — Divide the greater by the less, and then the divisor by the remainder loft, and so on until there is no remainder : the last divisor will be the GCM required. Ex. Find the GCM of 42 and 154. 126 28)42(1 28 £8 . • . 14 is the GCM required. This...
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The advanced lesson book, by E.T. Stevens and C. Hole

Edward Thomas Stevens - 1866 - 434 pages
...GREATEST COMMON MEASURE OF TWO NuxBERS. — Divide the greater by the less, and the former divisor by the remainder; and so on until there is no remainder. The last divisor is the greatest common measure required. To REDUCE A FRACTION TO ITS LOWEST TERMS. — Divide both...
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Arithmetic, for schools and colleges. (With key).

Richard Wormell - 1868 - 226 pages
...there be a remainder divide the first divisor by it. Afterwards divide the second divisor by the second remainder, and so on until there is no remainder. The last divisor is the greatest common measure of the two original numbers. If the last divisor be 1, the numbers have...
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