## Plane Geometry: And Supplements |

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**meeting**BC at Y ; EX 1 AC ,**meeting**BC at X. Prove that DY = EX . 62. In ∆ABC , ZA = 90 ° ; BD the bisector of ∠B meets AC at D ; DE BC at E. Prove that AB = BE . 63. In ∆ABC , AB = BC ; AB is extended through B to K , and CB through ...Page 401

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**meeting**BP at Y. YZ is drawn parallel to BC ,**meeting**PC at Z. XZ is drawn . Prove XYZ ~ △ AВС . ☆ 169 . ДАВC is inscribed in a circle having diameter AC . BD , the bisector of ∠B , meets AC at D and the circle at E. ( a ) Prove BA ...Page 405

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**meeting**DE ex- tended at F , and G. BFGC = ДАВС . Con . 219. In XYZW , place O on diagonal YW ; through O draw AC || XW ,**meeting**YX at A and ZW at C ; through O draw BD || XY ,**meeting**YZ at B and XW at D. Prove AODX = □ BOCZ . 220 ...### Contents

g The optional units from analytic geometry are included for three | 1 |

LinesAnglesPlanes | 11 |

W W | 24 |

Copyright | |

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### Common terms and phrases

ABCD acute angle adjoining figure altitude angle formed angles are equal apothem bisector bisects central angle chord conclusion congruent Construct converse coplanar corresponding sides diagonals diameter dihedral Draw drawn equal circles equidistant equilateral triangle exercises extended exterior angle figure for Ex Find frustum geometry given hypotenuse Hypothesis Informal proof inscribed intersect isosceles trapezoid isosceles triangle kind of angle lateral area length locus of points mean proportional measure meeting mid-point opposite sides parallel parallelogram perimeter perpendicular perpendicular-bisector Plan plane plane geometry Post postulate prism Prove pyramid quadrilateral radii radius ratio rectangle regular polygon rhombus right angle right circular right triangle secant segment similar sphere square Statements straight line Suggestion tangent theorem trapezoid trihedral angle vertex vertical angles Нур