Plane Geometry: And Supplements |
From inside the book
Results 1-3 of 30
Page 41
... Нур . Z1 = 25 Con . 23 = 25 F 6. Нур . Z1 = 25 Hypothesis . AB and CD Con . 2 = 26 7. Нур . 23 = 27 are straight lines , cut by EF . Con . 24 = 28 8. Нур . ∠2 is supp . of 27 . Con . 21 = 27 Note . §395 and §396 can be read now . 1. In ...
... Нур . Z1 = 25 Con . 23 = 25 F 6. Нур . Z1 = 25 Hypothesis . AB and CD Con . 2 = 26 7. Нур . 23 = 27 are straight lines , cut by EF . Con . 24 = 28 8. Нур . ∠2 is supp . of 27 . Con . 21 = 27 Note . §395 and §396 can be read now . 1. In ...
Page 55
... Нур . M bisects LN . L R M bisects PR . 1 2 Con . APML ≦ △ NMR M P N 3. Нур . RS = ST R SQ bisects TSR . Con . AQSR ≦ △ QST 1 S Q 2 Note . SQ = SQ . For authority you may 4. Нур . write Identical , meaning any quan- tity equals ...
... Нур . M bisects LN . L R M bisects PR . 1 2 Con . APML ≦ △ NMR M P N 3. Нур . RS = ST R SQ bisects TSR . Con . AQSR ≦ △ QST 1 S Q 2 Note . SQ = SQ . For authority you may 4. Нур . write Identical , meaning any quan- tity equals ...
Page 68
... Нур . GE = GF , AE = CF AB I GE , CD | GF Con . GB = GD Analysis . 1. GB = GD if A 3 C 4 E F △ GBE △ GDF . B D 2. In these triangles , GE = GF and_ZE = ∠F . △ GBE⊆ GDF if BЕ = DF . 3. Does BE = DF ? Yes , if ABE ACDF . 4. We know ...
... Нур . GE = GF , AE = CF AB I GE , CD | GF Con . GB = GD Analysis . 1. GB = GD if A 3 C 4 E F △ GBE △ GDF . B D 2. In these triangles , GE = GF and_ZE = ∠F . △ GBE⊆ GDF if BЕ = DF . 3. Does BE = DF ? Yes , if ABE ACDF . 4. We know ...
Contents
g The optional units from analytic geometry are included for three | 1 |
LinesAnglesPlanes | 11 |
W W | 24 |
Copyright | |
13 other sections not shown
Other editions - View all
Common terms and phrases
ABCD acute angle adjoining figure altitude angle formed angles are equal apothem bisector bisects central angle chord conclusion congruent Construct converse coplanar corresponding sides diagonals diameter dihedral Draw drawn equal circles equidistant equilateral triangle exercises extended exterior angle figure for Ex Find frustum geometry given hypotenuse Hypothesis Informal proof inscribed intersect isosceles trapezoid isosceles triangle kind of angle lateral area length locus of points mean proportional measure meeting mid-point opposite sides parallel parallelogram perimeter perpendicular perpendicular-bisector Plan plane plane geometry Post postulate prism Prove pyramid quadrilateral radii radius ratio rectangle regular polygon rhombus right angle right circular right triangle secant segment similar sphere square Statements straight line Suggestion tangent theorem trapezoid trihedral angle vertex vertical angles Нур