Place the sum down as in the last example, then mark off from the right of the dividend as many figures as there are ciphers in the divisor... The Complete Arithmetic - Page 72by Milton Browning Goff - 1876 - 452 pagesFull view - About this book
| Warren Colburn - Arithmetic - 1824 - 292 pages
...numbers will be made 10, 100, or 1000 times less than before. ^ Hence to divide by 10, 100, 1000, fyc. cut off from the right of the dividend as many figures as there are zeros in the divisor. The remaining figures will be the quotient, and the figures cut off will be the... | |
| Bézout - Arithmetic - 1825 - 258 pages
...when we have to divide by a number followed by ciphers, we can abridge the operation by separating on the right of the dividend as many figures as there are ciphers ; we divide the part which remains on the left by the significant figures of the divisor, and if there... | |
| Warren Colburn - Arithmetic - 1826 - 264 pages
...numbers will be made 10, 100, or 1000 times less than before. Hence to divide by 10, 100, 1000, Sfc. cut off from the right of the dividend as many figures as there are zeros in the divisor. The remaining figures will be the quotient, and the figures cut off will be the... | |
| Warren Colburn - 1829 - 258 pages
...will be made 10, 100, or 1000 times less than before. Hence to divide by 10, 100, 1000, ,$*c. cut of from the right of the dividend as many figures as there are zeros in the divisor. The remaining figures will be the quotient, and thi figures cut off will be the... | |
| W. F. Walker - Arithmetic - 1841 - 246 pages
...by 1, with any number of ciphers annexed, RULE. Point off, or suppose to be pointed off, by a comma, from the right of the dividend, as many figures as there are ciphers in the divisor. The figures thus pointed off, are a remainder, under which write the divisor. The figures... | |
| George Roberts Perkins - Arithmetic - 1849 - 346 pages
...remainder. Hence, the true remainder is 20 x 100+94=2094. From the above operations we deduce this RULE. Cut off from the right of the dividend as many...figures as there are ciphers at the right of the divisor ; divide what remains by the divisor without the. ciphers at its right. To the final, remainder annex... | |
| George Roberts Perkins - Arithmetic - 1850 - 364 pages
...Hence, the true remainder is 20 x 100+94 = 2094. From the above operations we deduce this RULE. Cat of from the right of the dividend as many figures as there are ciphers at the ri^ht of the divisor; divide what remains by the divisor without the ciphers at its right. To the final... | |
| George Roberts Perkins - Arithmetic - 1851 - 356 pages
...remainder. Hence, the true remainder is 20 x 100+94=2094. From the above operations we deduce this RULE. Cut off from the right of the dividend as many...as there are ciphers at the right of the divisor; divide vjhat remains by the divisor without the ciphers at its right. To the final remainder annex... | |
| Calvin Tracy - 1851 - 214 pages
...the reverse of multiplication, to divide by these same numbers, viz., 10, TOO, &c., we cut off front the right of the dividend as many figures as there are ciphers in the divisor. The figures on the left of the dividend point, constitute the quotient, and those on... | |
| John Fair Stoddard - Arithmetic - 1852 - 320 pages
...hills. ART. 49. To divide one number by another, when the divisor is followed by one or more ciphers. RULE. Cut off" from the right of the dividend as many figures as there are ciphers on the right of the divisor, then divide the remaining figures of the dividend by the divisor, after... | |
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