 | Zachariah Jess - Arithmetic - 1810 - 222 pages
...is the last term or greater extreme. Multiply the !ast term by the ratio, from the produft subtraft the first term, and divide the remainder by the ratio less one ; the quotient will be the sum of the series. - - . EXAMPLE S. - . j Sold 24 yards of Holland, at га.... | |
 | Arithmetic - 1811 - 210 pages
...first term, will give the last term, or greater extreme. > » 2. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by ratio less one for the sum of the series. - EXAMPLES. 1. A thrasher wrought 20 days, and- received... | |
 | Roswell Chamberlain Smith - 1814 - 300 pages
...find Oí* Sum of the Series, we /tare tin: following easy RULE. Multiply the last term, by the ratio, from the product subtract the first term, and divide the remainder by (he ratio, less 1 ; the quotient will be the sum of the eerie« required. « 9. If the extrem« be... | |
 | Arithmetic - 1817 - 214 pages
...the first term, will give the last term, or greater ex treats. 2 Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by ratio Jess (?ae for the sum of the series. EXAMPLE?. 1. A thresher wrought 20 da}-s, and received for... | |
 | Zachariah Jess - Arithmetic - 1824 - 228 pages
...first term, that product is the last term or greater extreme. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio less one ; the quotient will be the sum of the series. EXAMPLES. 1 Sold 24 yards of Holland, at 2d. for the... | |
 | Zachariah Jess - Arithmetic - 1824 - 224 pages
...first term, that product is the last -term or greater extreme. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio lessjone; the quotient will be the sum of the series. EXAMPLES. I Sold 24 yards of Holland, at 2d.... | |
 | Stephen Pike - Arithmetic - 1824 - 212 pages
...the first term, will give the last term, or greater extreme. 2. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by ratio less one for the sum of the series. EXAMPLES. 1. A thresher wrought 20 days, and received for... | |
 | Zachariah Jess - Arithmetic - 1827 - 226 pages
...the geometrical term. Then to find the sum of all the terms, multiply the last term by the ratio ; from the product, subtract the first term, and divide the remainder by the ratio, less one ; the quotient will be the sum of all the terms. Or shorter t thus : Involve the ratio to the power... | |
 | Thomas Tucker Smiley - 1830 - 188 pages
...term, and that product will be the last term. 3. Multiply the last term by the ratio; from the pro duct subtract the first term, and divide the remainder by the ratio, less 1, for the sum of the series. Questions. What is Geometrical Progression? What is the ratio ? By what... | |
 | Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...to find the sum of the series, we have the following easy HULE. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. ft If the extremes be 5 and 6400, and the... | |
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Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. 
