 | John Potter - Mathematics - 1753 - 568 pages
...6807 15883 4538 2269 329) 3284 2961 288.8437 3389) 32337 30501 1836 Remainder. Article 68. The Area of a Circle being given, to find the Circumference. Rule. Multiply the given Area by 12.566, and extract the Square Root of the Product, which Root will be the Circumference... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...scholar a right idea of the base and perpendicular, by marking U down on a slate, paper, *c. ART. 4. The diameter of a Circle being given, ;to find the Circumference. , RULE. As 7 : is to 22 : : ťo iť the given diameter : to t^e circumference. Or, more exactly, As 113 : is... | |
 | Nicolas Pike - Arithmetic - 1822 - 562 pages
...229)2298 . : . 2061 143-986188 2389)23761 21501 23989)226088 215901 10187 remainder. ART. 19. The Area of a Circle being given, to find the circumference. RULE. Multiply the given area by 12-566, and extract the square root of the product, which root will be the circumference... | |
 | Nicolas Pike - Arithmetic - 1822 - 536 pages
...circle are called quadrants : half the diameter as EB, is called the radiut, or semidiatneter. ART. 12. The Diameter of a Circle being given, to find the Circumference.* RULE. This may be done by either of the following proportions in whole numbers, as 7 is to 22, or more exactly,... | |
 | Ira Wanzer - Arithmetic - 1831 - 408 pages
...Duodecagon 4.82843 6.18182 7.69421 9.36564 11.19615 4 5 6 1.72048 2.59808 3.63391 7 PROBLEM IX. — The Diameter of a Circle being given, to find the Circumference. RULE. — As 7 is to 22, so is the diameter to the circumference, nearly : Or, more exactly, as 113 is to... | |
 | George Alfred - Arithmetic - 1834 - 336 pages
...or semi- с diameter, and is the distance taken in the compasses to describe the circle. PROBLEM 11. The diameter of a circle being given, to find the circumference. • RULE. This may be done by several proportions. 1. As 7 is to Й2, so is the diameter to the circumference... | |
 | Osman Call - Arithmetic - 1842 - 200 pages
...the diameter. What is the diameter of a circle, the area of which is 113,09? Ans. 11,999. THE AREA OF A CIRCLE BEING GIVEN, TO FIND THE CIRCUMFERENCE. RULE. — Multiply the given area by 12,566, and extract the square root of the product, and the root will be the circumference.... | |
 | Osman Call - Arithmetic - 1842 - 210 pages
...area of a regular nonagon, each of its sides being 5, and its perpendicular 6,8686935 ? Ans. 154,54+. THE DIAMETER OF A CIRCLE BEING GIVEN, TO FIND THE CIRCUMFERENCE. RULE. — As 7 are to 22, 50 is the diameter of a circle to ike circumference. Or, as 113 are to 355, or... | |
 | Thomas William Silloway - Carpentry - 1858 - 236 pages
...table extends to five places of decimals, it is exact enough for all practical purposes. PROBLEM VII. THE DIAMETER OF A CIRCLE BEING GIVEN, TO FIND THE CIRCUMFERENCE. RULE. — Multiply the diameter by 22, and divide the product by 1: the quotient will be the circumference. Or multiply the diameter by... | |
 | Janes Boddely Keene - 1861 - 104 pages
...circumference As 113 : 355 : : diameter : circumference As 1 : 3-1416 : : diamster : circumference The diameter of a circle being given, to find the circumference. RULE. — Make use of either of the ratios in the order above given. The circumference being given, to find... | |
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The diamoter of a circle being given, to find the circumference. RULE. 
