Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Elementary Algebra - Page 255by George William Myers, George Edward Atwood - 1916 - 338 pagesFull view - About this book
| John Davidson, Robert Scott (writing master) - Arithmetic - 1818 - 190 pages
...last part of the divisor. The tum of these three parts will be the complete divisor, which multiply **by the last figure of the root, subtract the product from the dividend, and to the remainder** bring down the next part for a new dividend. Proceed in the same manner as before to find the divisor... | |
| John Radford Young - Algebra - 1832 - 410 pages
...divisor's place, and the divisor will be completed. Multiply the complete divisor by the last term **of the root, subtract the product from the dividend, and to the remainder** connect the three next terms, and proceed as before. For (by Art. 37), the cube of a + b is a3 + 3a2¿... | |
| Benjamin Peirce - Algebra - 1837 - 288 pages
...which figure is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, **by the last figure of the root, subtract the product from the dividend, and to the remainder** bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
| Benjamin Peirce - Algebra - 1837 - 288 pages
...which figure is also to be placed at the right of the divisor. Multiply the divisor, thus augmented, **by the last figure of the root, subtract the product from the dividend, and to the remainder** bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
| John Radford Young - 1839 - 332 pages
...divisor's place, and the divisor will be completed. Multiply the complete divisor by the last term **of the root, subtract the product from the dividend, and to the remainder** connect the three next terms, and proceed as before. For (by Art. 37,) the cube of a+b is a»+ 3a2¿>... | |
| John Husband (math. master, Berwick.) - 1841 - 126 pages
...right ; add together these two lines for the complete divisor; multiply the sum by the second figure in **the root ; subtract the product from the dividend, and to the remainder annex the** third period for a new dividend. Place the square of the second figure of the root under the complete... | |
| George Roberts Perkins - Arithmetic - 1841 - 274 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and **subtract the product from the dividend, and to the remainder annex the next** period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR, add the Jastfgure of the root, for... | |
| James Bates Thomson - Arithmetic - 1846 - 398 pages
...the right of the root, also on the right of the partial divisor ; multiply the divisor thus completed **by the last figure of the root ; subtract the product from. the dividend, and to the remainder** bring down the next period for a new dividend, as before. IV. Double the root already found for a new... | |
| James Bates Thomson - Arithmetic - 1846 - 336 pages
...the right of the root, also on the right of the partial divisor ; multiply the divisor thus completed **by the last figure of the root ; subtract the product from the dividend, and to the remainder** bring down the next period for a new dividend, as before. IV. Double the root already found for a new... | |
| George Roberts Perkins - Arithmetic - 1846 - 266 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figurt of the root, and **subtract the product from the dividend, and to the remainder annex the next period, for a** SECOND DIVIDEND. IV. To the last TRUE DIVISOR, add the last figure of the not, for a new TRIAL DIVISOR,... | |
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