 | Adrien Marie Legendre - Geometry - 1822 - 394 pages
...will be isosceles. First. Suppose the side AB=AC ; we shall have the angle C=B. For, if the arc AD be drawn from the vertex A to the middle point D of...Proposition, their angles will be equal ; therefore B=C. Secondly. Suppose the angle B— C ; we shall have the side AC=AB For, if not, let AB be the greater... | |
 | Peter Nicholson - Architecture - 1823 - 210 pages
...equal. Let the side AB be equal to AC ; then shall the angle C equal the A. angle B. For, suppose AD to be drawn from the vertex A to the middle point D, of the base BC ; then the two triangles ADB, ADC, will have the two sides AB, BD, of the one equal to the two sides... | |
 | Adrien Marie Legendre - Geometry - 1828 - 346 pages
...triangle is isosceles. First, Suppose the side AB=AC ; we shall have the angle C=B. For, if the arc AD be drawn from the vertex A to the middle point D of...respectively equal to the corresponding sides of the other, namelv, AD common, BD=DC, and AB=AC : "hence by the last Proposition, their angles will be equal ;... | |
 | Adrien Marie Legendre - Geometry - 1830 - 344 pages
...triangle is isosceles. O, First- Suppose the side AB=AC; we shall have the angle C =B. For, if the arc AD be drawn from the vertex A to the middle point D of...sides of the other, namely, AD common, BD==DC, and AB=AC : hence by the last Proposition, their angles will be equal ; therefore B— C. Secondly. Suppose... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...triangle is isosceles. First. Suppose the side AB= AC ; we shall have the angle C=B. For, if the arc AD be drawn from the vertex A to the middle po.int D...sides of the other, namely, AD common, BD=DC, and ABAC : hence by the last Proposition, their angles will be equal ; therefore, B— C. ', Secondly.... | |
 | Adrien Marie Legendre - Geometry - 1837 - 376 pages
...triangle is isosceles. First. Suppose the side AB=AC; we shall have the angle C=B. For, if the arc AD be drawn from the vertex A to the middle point D of...corresponding sides of the other, namely, AD common, BD = DC, and AB = AC : hence by the last Proposition, their angles will be equal ; therefore, B = C.... | |
 | Nathan Scholfield - Conic sections - 1845 - 542 pages
...triangle ABC ; that is, besides the three parts equal by hypothesis, we shall have the side BC— FG, the angle ABC=EFG, and the angle ACB=EGF. PROPOSITION...Proposition, their angles will be equal ; therefore B— C. Secondly. Suppose the angle B=C ; we shall have the side AC=AB. For, if not, let AB be the... | |
 | George Roberts Perkins - Geometry - 1847 - 326 pages
...will be isosceles. First. Suppose the side AB=AC ; we shall have the angle C = B. For, if the arc AD be drawn from the vertex A to the middle point D of...sides of the other, namely, AD common, BD=DC, and AB=AC : hence, by the last proposition, their angles will be equal ; therefore B = C. Secondly. Suppose... | |
 | Charles Davies - Trigonometry - 1849 - 372 pages
...triangle is isosceles. First. Suppose the side AB = AC; we shall have the angle C=B. For, if the arc AD be drawn from the vertex A to the middle point D of...corresponding sides of the other, namely, AD common, BD —DC, and AB = AC: hence by the last Proposition, their angles will be equal; therefore, B = C.... | |
 | George Roberts Perkins - Geometry - 1850 - 332 pages
...will be isosceles. First. Suppose the side AB = AC , we shall have the angle C = B. For, if the arc AD be drawn from the vertex A to the middle point D of...respectively equal to the corresponding sides of the other,-namely, AD common, BD = DC, and AB = AC: hence, by the last proposition, their angles will be... | |
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For, if the arc AD be drawn from the vertex A to the middle point D of the base, the two triangles ABD, ACD will have all the sides of the one respectively equal to the corresponding sides of the other, namely, AD common, BD=DC, and AB= AC : hence by... 
