## Plane Geometry |

### From inside the book

Results 1-5 of 49

Page 55

...

...

**ABCD**by means of § 63 ? Hence begin by drawing the bisector CD of C. Draw an accurate figure with straight- edge and compasses , and write the complete proof . ≤ 71. Corollary 1. — An equilateral triangle is also equiangular . The ... Page 67

...

...

**ABCD**is a parallelogram . Conclusion . AB DC and AD = BC . Proof . 1 .**ABCD**is a parallelogram . Hyp . Def . 2. ... AB DC and AD || BC . 3. Draw diagonal DB . 4. Then in A ABD and △ BCD , DB is a common side . ABD = △ BDC and ≤ ADB ... Page 68

...

...

**ABCD**, AB = DC_and**ABCD**is a parallelogram . Suggestions . Draw diagonal DB . It may be proved that**ABCD**is a parallelogram by proving what lines parallel ? For proving these lines parallel , what angles should be proved equal ? How may ... Page 69

...

...

**ABCD**is the required parallelogram . Proof . 1. BC = AD and DC = AB . 2. ..**ABCD**is a parallelogram . 3. ≤ BAD = ≤ x , AB = m , AD = n . Construction § 87 Construction 4. Hence**ABCD**is the required parallelogram . EXERCISES C D 1 ... Page 70

...

...

**ABCD**, LA = C and LB = LD . Conclusion .**ABCD**is a parallelogram . Suggestions . It may be proved that AB DC by first proving that B and C are supplementary . Draw AC . What is the sum of the angles of AABC and △ ADC , or of**ABCD**...### Other editions - View all

### Common terms and phrases

AABC ABCD AC and BD acute angle altitude angle equal angles are equal apothem base bisects central angle chord circle with center circumscribed compasses and straightedge Conclusion congruent Construct a triangle Corollary corresponding sides decagon diagonals diameter distance Divide a given drawn equal angles equal arcs equal circles equidistant equilateral triangle EXERCISES exterior angles follows formed geometry given angle given circle given line given line-segment given point given triangle Hence hypotenuse Hypothesis inscribed angle intercepted internally tangent intersect isosceles triangle locus measure medians middle points number of sides parallel lines parallelogram perimeter perpendicular bisector point of contact proof in full proof is left quadrilateral radii radius ratio rectangle regular polygon rhombus right angle right triangle secant segment Show similar polygons square straight angle straight line student SUGGESTION tangent trapezoid vertex Write the proof

### Popular passages

Page 130 - If two triangles have two sides of one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the first is greater than the third side of the second.

Page 76 - The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it 46 INTERCEPTS BY PARALLEL LINES.

Page 223 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.

Page 4 - PERIPHERY of a circle is its entire bounding line ; or it is a curved line, all points of which are equally distant from a point within called the center.

Page 21 - If the first of three quantities is greater than the second, and the second is greater than the third, then the first is greater than the third.

Page 222 - Two triangles having an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles.

Page 131 - ... if two triangles have two sides of one equal, respectively, to two sides of the other...

Page 72 - There are three important theorems in geometry stating the conditions under which two triangles are congruent: 1. Two triangles are congruent if two sides and the included angle of one are equal respectively to two sides and the included angle of the other.

Page 258 - S' denote the areas of two circles, R and R' their radii, and D and D' their diameters. Then, I . 5*1 = =»!. That is, the areas of two circles are to each other as the squares of their radii, or as the squares of their diameters.

Page 197 - In any triangle, the square of the side opposite an acute angle is equal to the sum of the squares of the other two sides, minus twice the product of one of these sides and the projection of the other side upon it.