therefore the area of a trapezoid is equal to the product of its altitude and the line joining the middle points of the sides •which are not parallel. THEOREM VI. 16. A line drawn parallel to one side of a triangle divides An Elementary Geometry - Page 21by William Frothingham Bradbury - 1872 - 110 pagesFull view - About this book
| Adrien Marie Legendre - Geometry - 1819 - 574 pages
...expressed also by EFx III; that is, it is equal to the product of the altitude of the trapezoid by the line joining the middle points of the sides which are not •parallel. THEOREM. f\g. 106. 180. If a line AC (fig. 106) is divided into two parts AB, BC, the square described upon... | |
| Adrien Marie Legendre - 1825 - 570 pages
...be expressed also by EF x HI; that is, it is equal to the product of the altitude of thetrapezoid by the line joining the middle points of the sides which are not parallel. . THEOREM. Fig. 106. '80. If a line AC (fig. 106) is divided into two parts AB, BC, the square described upon... | |
| Adrien Marie Legendre, John Farrar - Geometry - 1825 - 294 pages
...expressed also by EF X. HI; that is, it is equal to the product of the altitude of the trapezoid by the line joining the middle points of the sides which are not parallel. THEOREM. Fig. 106. 180. If a line AC (fig. 106) is divided into two parts AB, BC, the square described upon... | |
| Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...expressed also by EF X HI; that is, it is equal to the product of the altitude of the trapezoid by the line joining the middle points of the sides which are not parallel. THEOREM. Fig. 106. 180. If a line AC (fig. 106) is divided into two parts AB, BC, the square described upon... | |
| Timothy Walker - Geometry - 1829 - 156 pages
...area of a regular polygon is equal to the product of its perimeter by half the radius 103. THEOREM.— The area of a trapezoid is equal to the product of its altitude by half the sum of its paral1el sides. By the altitude of a trapezoid we mean the perpendicular let... | |
| Timothy Walker - Geometry - 1829 - 138 pages
...opposite side, produced if necessary; and by the base the side upon which the perpendicular falls. 103. —The area of a trapezoid is equal to the product of '. its altitude by half the sum of its parallel sides—. By the altitude of a trapezoid we mean the perpendicular... | |
| Timothy Walker - Geometry - 1831 - 166 pages
...(84). But the area of ABCD=ADxC E (101). Therefore the area of ACD=half of A DxC E. 103. THEOREM.— The area of a trapezoid is equal to the product of its altitude by half the Sinn of its parallel sides. By the altitude of a trapezoid we mean the perpendicular let... | |
| Benjamin Peirce - Geometry - 1837 - 216 pages
...AB + CD, HI= ±(AB+ CD). 255. Corollary. The area of a trapezoid is the product of its altitude by the line joining the middle points of the sides which are not parallel. 256. Theorem. The square described upon the hypothenuse of a right triangle is equivalent to the sum... | |
| Charles Waterhouse - Arithmetic - 1842 - 178 pages
...the other two sides. 16. Every triangle is half of a parallelogram of the same base and'altitude. 17. The area of a trapezoid is equal to the product of its altitude by half the sum of its parallel sides. 18. A line drawn so as to divide a triangle parallel to its... | |
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