 | Bewick Bridge - Algebra - 1818 - 254 pages
...consequently the number of these dots will shew the number of figures contained in the square root of i the the given number. From hence it also follows,...contained in the first of those periods, reckoning frem the left. Thus, in the case of 5336 1 (whose square root is a number consisting of three figures)... | |
 | James Ryan, Robert Adrain - Algebra - 1824 - 542 pages
...(61), or in the last but one (33), it must be found in the first period (5) ; consequently the first figure of the root will be the square root of the greatest square number contained in 5 ; and this number is 4, the first figure of the root will be 2. The remainder of the operation will... | |
 | James Ryan - Algebra - 1824 - 550 pages
...(61), or in the last but one (33), it must be found in the first period (5) ; consequently the first figure of the root will be the square root of the greatest square number contained in 5 ; and this number is 4, the first figure of the root will be 2. The remainder of the operation will... | |
 | James Ryan - Algebra - 1826 - 430 pages
...the greatest square root contained in the first of those periods reckoning from the left. . ... ber consisting of three figures) ; since the square of...hundred's place cannot be found either in the last period (61), or in the last but one (33), it must be found in the first period (5) ; consequently the first... | |
 | James Ryan, Robert Adrain - Algebra - 1835 - 388 pages
...given number. From hence it follows, that the first figure of the root will be the greatest square root contained in the first of those periods reckoning...Thus, in the case of 53361 (whose square root is a nuniber consisting of three figures) ; since the square of the figure standing in the hundred's place... | |
 | Bewick Bridge - Algebra - 1839 - 280 pages
...(61), or in the last but one (33), it must be found in the first period (5) ; consequently the first figure of the root will be the square root of the greatest square number contained in 5 ; and as this number is 4, the first figure of the root will be 2. The remainder of the operation... | |
 | Elias Loomis - Algebra - 1855 - 356 pages
...left, the number of figures in the root will be equal to the number of periods. (278.) II. The first figure of the root will be the square root of the greatest square number contained in the first period on the left. For the square of tens can give no figure in the first right hand period ; the... | |
 | Elias Loomis - Algebra - 1856 - 280 pages
...left, the number of figures in the root will be equal to the number of periods. (138.) II. The first figure of the root will be the square root of the greatest square number contained in the first period on the left. Every number consisting of more than one figure may be regarded as composed of... | |
 | Elias Loomis - Algebra - 1858 - 394 pages
...left, the number of figures in the root will be equal to the number of periods. (278.) II. The first figure of the root will be the square root of the greatest square number contained in the first period on the left. For the square of tens can give no figure in the first right hand period ; the... | |
 | John Flint (inspector of schools.) - 1862 - 152 pages
...pointing to the left in whole numbers, and from the left or decimal point to the right in decimals. Write the square root of the greatest square number contained in the first period to the left, as the first figure of the root, and subtract its square from the first period,... | |
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Thus, in the case of 53361 (whose square root is a number consisting of three figures) ; since the square of the figure standing in the hundred's place cannot be found either in the last period... 
