 | Alexander Malcolm - Algebra - 1730 - 702 pages
...fliewn that</x«— -i=s/— -л. and dividing equally by » — i, it is</= *. Ж *^~ I 2. For ti multiply the Sum of the Extremes by the Number of Terms, and take half of the Produo, it's the Sum : Thus *= *"HX*. E*a*,fk: - = 3./=iy.» = 7. then is /==6, —... | |
 | Mathematics - 1801 - 446 pages
...term, the last term, and the number of terms behtg given, to find the sum of all the terms. RULE.* Multiply the sum of the extremes by the number of terms,, and half the product will be the answer. EXAMPLES. * Suppose another series of the same kind with the given... | |
 | Nicolas Pike - Algebra - 1808 - 470 pages
...term, the last term, and the number of terms being given, tojind the sum of all the terms. RuLE.f — Multiply the sum of the extremes by the number of terms, and half the producl will be the answer. EXAMPLES. • The difference of the firft and laft terms evidently... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...Problems ; but mast of them are best understood by an algebraic process, iand »re here omiti.".' t RULE. Multiply the sum of the extremes by the number of terms, and half the product wiH be the answer. EXAMPLE8. ). The first term of an arithmetical series is 3, the... | |
 | Arithmetic - 1818 - 264 pages
...first term, the last term, and the number of terms being given, to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of terms,," and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical progression is... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...Problems ; but most of them are best understood by an algebraic process, nnd are here omitted. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the answer.' EXAMPLES. ^ . 1. The first term of an arithmetical series is... | |
 | Phinehas Merrill - Arithmetic - 1819 - 116 pages
...and the number of terme being given, to find the aggregate, or total вит of alt the terns. RULE —Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. •. > i •« 1. The first term is 2, the last term... | |
 | Zadock Thompson - Arithmetic - 1826 - 176 pages
...first term, the last term, and the number of terms given, to find the sum of all the terms. RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. Examples. 1. The first term of an arithmetical progression is... | |
 | B. M. Tyler - Arithmetic - 1827 - 308 pages
...multiplying the sum of the extremes by the number of terms, gives double the sum of the series. RULE. Multiply the sum of the extremes by the number of terms, and divide the product by 2 ; or multiply half the sum of the extremes by the number of terms. 1 1. If the first term of an arithmetical... | |
 | James Ryan - Arithmetic - 1827 - 290 pages
...— The extremes and the number of terms leing given, to find the sum of the series. 206. RULE. — Multiply the sum of the extremes by the number of terms, and take half the product. * Thereason of this operation will be manifest from the consideration, that... | |
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RULE. Multiply the sum of the extremes by the number of terms, and divide the product by 2. 
