It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of the first term. 282. Every affected quadratic may be made to assume the form of aV ± 2 abx = c. To solve such an equation... Elements of Algebra - Page 192by George Albert Wentworth - 1881 - 380 pagesFull view - About this book
| William Frothingham Bradbury - Algebra - 1868 - 264 pages
...completed without multiplying the equation, by adding to both members the square of the quotient arising from dividing the second term by twice the square root of the first. This method also becomes the same as the first method when the coefficient of z2 is unity. NOTE 3.... | |
| William Frothingham Bradbury - Algebra - 1877 - 302 pages
...completed without multiplying the equation, by adding to both members the square of the quotient arising from dividing the second term by twice the square root of the first. This method also becomes the same as the first method when the coefficient of 3? is unity. NOTE 3.... | |
| Webster Wells - Algebra - 1885 - 370 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9яr — 5ж= 4. The quotient of the second term divided by twice the square... | |
| Webster Wells - Algebra - 1885 - 382 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9 яr — 5 ж = 4. The quotient of the second term divided by twice the 5 5... | |
| Webster Wells - 1885 - 368 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9 ar — 5 ж = 4. The quotient of the second term divided by twice the 5 5 square... | |
| George Albert Wentworth - Algebra - 1886 - 284 pages
...abx lacks only the third term, V, of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of thefirst term. 218. Every affected quadratic may he made to assume the form of a?x2 ± 2 abx = c. The... | |
| George Albert Wentworth - Algebra - 1887 - 268 pages
...square root of the first term. 218. Every affected quadratic may be made to assume the form of aV ± 2 abx = c. The first step in the solution of such...of the quotient obtained from, dividing the second ferra by twice the square root of the first term. The second step is to extract the square root of... | |
| George Albert Wentworth - Algebra - 1888 - 514 pages
...third term 62 of being a perfect square. This third term is the square of the quotient obtained by dividing the second term by twice the square root of the first term. Every affected quadratic may be made to assume the form aV ± 2abx = c (§ 131). To solve such an equation... | |
| George Albert Wentworth - Algebra - 1891 - 380 pages
...quadratic may be made to assume the form of a2ar1 ± 2 abx = c. To solve such an equation : The first step is to complete the square; that is, to add to each...first term. The second step is to extract the square rdbt of each side of the resulting equation. The third and last step is to reduce the two resulting... | |
| George Albert Wentworth - Algebra - 1891 - 380 pages
...abx lacks only the third term, V, of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing...second term by twice the square root of the first term. 282. Every affected quadratic may be made to assume the form of aV ± 2 abx = c. To solve such an equation... | |
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