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" Complete the square by adding to both members the square of half the coefficient of x. Extract the square root of both members, and solve the sim259. "
Elementary Algebra - Page 275
by Walter Randall Marsh - 1905 - 395 pages
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A Treatise on Algebra

Elias Loomis - Algebra - 1855 - 356 pages
...which may be solved in the usual manner. EXAMPLE 1. Solve the equation a;'— 10x= — 16. Completing the square by adding to each member the square of half the coefficient of the second term, we have x'— Wx+25—25— 16=9. Extracting the root, x— 5= ±3. . Hence a;=5±3....
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The Elements of Algebra

Elias Loomis - Algebra - 1856 - 280 pages
...other side of the equation. Ex. 1. What are the values of a; in the equation x'-IQx=-161 Completing the square by adding to each member the square of half the coefficient of the secx^ erm, we have z'-10a;+25=25- 6=0 Extracting the root, z-5=±3. Hence a;=5±3=8 or 2. Thus...
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A Treatise on Algebra

Elias Loomis - Algebra - 1858 - 394 pages
...which may be solved in the usual manner. EXAMPLE 1. Solve the equation x'— 10x= — 16. Completing the square by adding to each member the square of half the coefficient of the second term, we have a;'— 10a;+25=25- 16=9. Extracting the root, x—5= ±3. Hence a;=5±3. x=5-3=2....
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A Treatise on Algebra

Elias Loomis - Algebra - 1864 - 386 pages
...which may be solved in the usual manner. EXAMPLE 1. Solve the equation a; ' — 10a;= —16. Completing the square by adding to each member the square of half the coefficient of the second term, we have a;'- 1(te+25=25-16=9. Extracting the root, x—5= ±3. Hence a;=5±3. Ans....
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The Analyst: A Monthly Journal of Pure and Applied Mathematics, Volumes 1-2

Mathematics - 1874 - 430 pages
...the whole eqution, then multiply the right hand member by the coefficient of j?, to the product add the square of half the coefficient of x, extract the square root of the result, connect this square root with half the coefficient of x with its sign changed and divide...
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University Algebra

Webster Wells - Algebra - 1879 - 468 pages
...result. BULE. Reduce the equation to the form x2 + px = q. Complete the square by adding to both members the square of half the coefficient of x. Extract the square root of both members, and solve the simple equation thus found. 1. Solve the equation x2 — 3 x = 4. Completing...
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The Analyst, Volumes 1-4

Mathematics - 1874 - 834 pages
...the whole eqution, then multiply the right hand member by the coefficient of .v2, to the product add the square of half the coefficient of x, extract the square root of the result, connect this square root with half the coefficient of x with its sign changed and divide...
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A Complete Course in Algebra for Academies and High Schools

Webster Wells - Algebra - 1885 - 324 pages
...rule: Reduce the equation to the, form я? -\-px = q. Complete the square by adding to both members the square of half the coefficient of x. Extract the square root of both members, and solve the simple equation thus formed. 1. Solve the equation 3ar — Sx= — 4. -rk....
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College Algebra: For the Use of Academies, Colleges, and Scientific Schools ...

Edward Albert Bowser - Algebra - 1888 - 868 pages
...member, and the coefficient of x1 is +1 ; complete the square by adding to each member of the equation the square of half the coefficient of x; extract the square root of both members, and solve the resulting simple equation. NOTE 4. — There are other ways of completing...
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The Academic Algebra

William Frothingham Bradbury - Algebra - 1889 - 444 pages
...equation can be reduced by the following Bu1e. Reduce the equation to the form xz + bx = c, and add to each member the square of half the coefficient of x. Extract the square root of each member, and then reduce as in simple equations. NOTE 1. Reducing an equation to the form я? -f bx = с means,...
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