 | Mathematics - 1801 - 446 pages
...denominator of the given aliquot part, aed the quotient will bi the logarithm of the root sought. 4. Subtract the principal from the amount, and the remainder will be the interest. ' EXAMPLES. i. What is the compound interest of 500!. for 4 years, at 5 per cent. per annum ? 1*05... | |
 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...956i 10s. 4,125d. in 8J years ? Ans. 51 per cent. CASE IV, The amount, principa , and rate per cent, given, to find the time. RULE. — Subtract the principal from the amount; divide the remainder by the product of the ratio and principal ; and the quotient will be the time.... | |
 | Arithmetic - 1817 - 214 pages
...476 dois. CASE С. To find the rate per cent, when the amount, time and principal are given. ROLE. Subtract the principal from the amount, and the remainder will be the interest for the given time : then, As the principal, Is to one hundred pounds, or dollars, So is the interest... | |
 | Arithmetic - 1818 - 264 pages
...^62.253750 in 3 years and 3 months ? Ans. 6 per cent. CASE IV. The AMOUNT, PRINCIPAL, and RATE per cent given, to find the TIME. RULE Subtract the principal from the amount, divide the remainder by the product of the rUio and principal ; and the quotient will be the time.... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...9561. 10s. 4,l25d. in 8| years ? Jlns. 5$ per cent. CASE IV. The amount, principal, and rate per cent, given, to find the time. RULE. Subtract the principal from the amount f divide the remainder by the product of the ratio and principal ; and the quotient will be the time.... | |
 | Phinehas Merrill - Arithmetic - 1819 - 116 pages
...years. 3. Muii ¡ply this power by the principal, and the product •will be the amount required. 4. Subtract the principal from the amount, and the remainder will be the interest. EXAMPLES. 1. What is the Compound interest of £.500 for 4 years, at 5 per cent ? the amount is in-uutved... | |
 | Stephen Pike - Arithmetic - 1824 - 212 pages
...Ans. 476 dollars. CASE 6. To find the rate per cent. when the amount, time and principal are given. RULE. Subtract the principal from the amount, and the remainder will be the interest for the given time: then, As the principal, Is to one hundred pounds or dollars, So rs the interest... | |
 | Roswell Chamberlain Smith - Arithmetic - 1827 - 216 pages
...yrs. orno, and 15 days, at 6 per cent ? A. $600. CASE IV. — When the principal, rate, and amount are given to find the time. RULE. — Subtract the principal from the amount, and divide the remainder, by the interest of the given sum for 1 year. Exercises for the Slate. In what... | |
 | Arithmetic - 1831 - 210 pages
...Ans. 476 dollars. CASE 6. To find the rate per cent, when the amount, time and principal are given. RULE. Subtract the principal from the amount, and the remainder will be the interest for the given time: then, As the principal, Is to one hundred pounds or dollars, So is the interest... | |
 | Samuel Read Hall - Arithmetic - 1832 - 294 pages
...simple interest ; it will then show the amount of principal and interest for the given number of years. Subtract the principal from the amount, and the remainder will be the compound interest. When there are months and days, first find the compound interest for the given years... | |
| |
The principal, rate per cent., and amount given, to find the time. RULE. Subtract the principal from the amount, and the remainder will be the interest. 
