...t/x - 3 = 2 V2# +1-3. Squaring both sides, .-. 9 (#-3) = 4(2o;+l)-12 \/2#+l+9. Transpose the radical to one side of the equation, and all the other terms to the other side, and simplify, Squaring both sides, . • . 1 44 (2x + 1 ) = 1 600 - 80x + x2. .-. ^-368^+1456 = 0,...

...Thus, if 8 x = 24, then 8ж + 4 = 24 + 4, 8ж-4 = 24-4, 4 X 8ж = 4 X 24, and 8x -r- 4 = 24 -5- 4. 91. Transposition of Terms. It becomes necessary in solving...right side. This can be done by first subtracting 1x from both sides (Ax. 2), which gives 9s- 11 = 70, and then adding 11 to these equals (Ax. 1), which...

...equal. Thus, if 8 a; = 24, then 8ж + 4 = 24 + 4, 8ж-4 = 24-4, 4х8ж = 4х24, and 8жн-4 = 24 н-4. symbol for the unknown number to one side of the equation,...right side. This can be done by first subtracting Чx from both sides (Ax. 2), which gives 9ж-11=70, and then adding 11 to these equals (Ax. 1), which...

...Thus, if 8x = 24, then 8ж + 4 = 24 + 4, 8ж - 4 = 24 - 4, 4 X 8x = 4 X 24, and 8x -н 4 = 24 -*- 4. symbol for the unknown number to one side of the equation,...examples : (1) Find the number for which x stands when First subtract 7 x from both sides (Ax. 2), which gives 9x -11 = 70. Then add 11 to these equals (Ax....

...equal. Thus, if 8a; = 24, then 8x + 4 = 24 + 4, 8* - 4 = 24 - 4, 4X8я = 4X24, and 8a; н- 4 = 24-=- 4. symbol for the unknown number to one side of the equation,...examples : (1) Find the number for which x stands when 16* -11 = 7* +70. The first object to be attained is to get all the terms which contain x on the left...

...operations which are indicated. Then transpose all the terms into which the unknown quantity enters to one side of the equation, and all the other terms to the other side. Next combine all the terms which contain the unknown quantity into one term, and divide by the coefficient...

...in solving simple equations to bring all the terms that contain the symbols for the unknown numbers to one side of the equation, and all the other terms to the other side. This process is called transposing the terms. 1. Find the number for which x stands when x - b = a. Add...

...in solving simple equations to bring all the terms that contain the symbols for the unknown numbers to one side of the equation, and all the other terms to the other side. This process is called transposing the terms. 1. Find the number for which x stands when x — b = a. Add...

...solution of a simple equation may be found. Transpose all the terms which contain the unknown quantity to one side of the equation, and all the other terms to the other side, changing the sign of any term so transposed. Next combine all the terms which contain the unknown quantity...

...solve an equation having one unknown quantity, transpose all the terms involving the unknown quantity to one side of the equation, and all the other terms to the other side; combine like terms, and divide both sides by the coefficient of the unknown quantity. Solve Sx - 29...