| Aeronautical Society of Great Britain - Aeronautics - 1883 - 494 pages
...base b and altitude a be rotated about its base, the resistance which it experiences is JB. But the area of a triangle is equal to one half the product of its base on altitude, and coasequently that spoken of has only •£ the area of the rectangle, therefore,... | |
| Isaac Sharpless - Geometry - 1879 - 282 pages
...altitude. For it is equal to a rectangle of the same base and altitude (I. 33). Corollary 2.—The area of a triangle is equal to one half the product of its base and altitude. For a triangle is one half a rectangle of the same base and altitude (I. 35,... | |
| George Albert Wentworth - Geometry, Analytic - 1886 - 334 pages
...^iy2 — 2-sy2 .-. area =| [a?i (y2 - ys) + x^ (ys -yi)+ xs (j/ij/2)]. [13] SOLUTION II. Since the area of a triangle is equal to one half the product of its base and its altitude, this problem may be solved as follows : (i) Find the length of any side... | |
| William Shaffer Hall - Measurement - 1893 - 88 pages
...20. To find the area of a triangle, when two sides and their included angle are given. [12] RULE: The area of a triangle is equal to one- half the product of two sides into the sine of their included angle. PIG. 4. Proof Let ABC, Fig. 4, represent a plane triangle,... | |
| Wm. M. Peck - 1894 - 310 pages
...perpendicular distance from the base, or the base produced, to the Fi g- 6 vertex. (Fig. 5). | e. The area of a triangle is equal to one \ half the product of the numbers represent- \* ing its base and height. (Fig. 6). In a right triangle the following names are... | |
| Charles Ambrose Van Velzer, George Clinton Shutts - Geometry - 1894 - 524 pages
...the original polygon. Continue the process until the polygon is reduced to a triangle. Ex. 189. The area of a triangle is equal to one half the product of its perimeter by the radius of the inscribed circle. PROPOSITION XX. PROBLEM. 286. To find two straight... | |
| Adelia Roberts Hornbrook - Geometry - 1895 - 222 pages
...triangles in the same way, by taking half the product of the base and altitude. PRINCIPLE 22. — The area of a triangle is equal to one half the product of its base and altitude. 96. Draw a triangle and show in what way you find its area. 97. Find the area... | |
| Middlesex Alfred Bailey - Arithmetic - 1897 - 332 pages
...altitude. IV. The area of a parallelogram is equal to the product of its base by its altitude. V. The area of a triangle is equal to one half the product of its base by its altitude. VI. TJie area of a Mangle is equal to the square root of the continued product... | |
| Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 374 pages
...parallelograms having equal altitudes are to each other as their bases. PROPOSITION VI. THEOREM 370. The area of a triangle is equal to one -half the product of its base and altitude. 112 GIVEN the triangle ABC with base b and altitude a. To PROVE area AB C =... | |
| Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 376 pages
...parallelograms having equal altitudes are to each other as their bases. PROPOSITION VI. THEOREM 370. The area of a triangle is equal to one -half the product of its base and altitude. b B GIVEN the triangle ABC with base b and altitude a. To PROVE area ABC = iax... | |
| |