| Mathematics - 1801 - 658 pages
...base 8 feet 6 inches. Ans, PROBLEM VI. fo find tin convex surface of the frustum »fa right com. RULE. Multiply the sum of the perimeters of the two ends...frustum, and half the product will be the surface. EXAMPLES. I. If the circumferences of the two ends be I2'5 *nd io'3, and the slant height AD 14; required... | |
| Thomas Keith - 1817 - 306 pages
...41), and this product by the height, for the solidity. Nate. To find the superficies, multiply half the sum of the perimeters of the two ends by the slant height, and the produce will be the suiface of the sides ; to which add the areas of the cuds, and the sum... | |
| Anthony Nesbit - Surveying - 1824 - 476 pages
...will be the solidity. Nett. The surface of the frustum of a pyramid may be found thus : Multiply half the sum of the perimeters of the two ends, by the slant height, and the product will be the surface of the sides; to which add the areas of the ends, and the sum will... | |
| John Bonnycastle - Geometry - 1829 - 256 pages
...surface? Ans. 98.09375. PROBLEM VII. To find the convex surface of the frustum of a right cone, ' RULE.* Multiply the sum of the perimeters of the two ends, by the slant height of the frustum, and half the product will be the surface required. 2. What is the convex surface of... | |
| Thomas Curtis - Aeronautics - 1829 - 810 pages
...XXV.* To find the convex surface of the frustum of a right cone or pyramid. Rule. — Multiply half the sum of the perimeters of the two ends by the slant height of the frustum, and the product will be the area. Example. — The circumferences of the ends of the... | |
| John Nicholson (Civil engineer) - Building - 1830 - 240 pages
...To find the Convex Surfaceof the Frustum of a Right Cone Multiply the sum of the perimeters of tbe two ends by the slant height or side of the frustum,...the two ends be 12-5 and 10'3, and the slant height 14, required the convex surface of the frustum. 12'5 10-3 2 ) 319;2 159-6 Ansr. Prob. 7. To find the... | |
| Dudley Leavitt - Mathematics - 1830 - 154 pages
...content or convex surface of the frustum of a cone. Rule. Multiply the sum of the circumferences of both ends, by the slant height or side of the frustum, and half the product is the content sought. Exam. What is the superficial content of the outside of a wash tub, that is... | |
| William Templeton (engineer.) - 1833 - 224 pages
...28=2932.]6cubifiincheS) and MENSURATION PROBLEM III. To find the Surface of the Frustum of a Cone or Pyramid, RULE. — Multiply the sum of the perimeters of the two ends by the slant height, and half the product will be the slant surface; to which add the areas of the two ends, and the product... | |
| William Galbraith - Astronomy - 1834 - 454 pages
...area of the base by one-third the perpendicular height. 3. Frustum of a. Pyramid. (1.) Multiply half the sum of the perimeters of the two ends by the slant height. To this add the areas of the two ends, the sum will be the whole surface. (2.) Capacity. Add a diameter... | |
| James Gallier - Building - 1836 - 228 pages
...'will be the surface. To find the Convex Surface of a Frustum of a Right Cone or Pyramid. RULE. — Multiply the sum of the perimeters of the two ends...frustum, and half the product will be the surface required. To find the Solidity of a Cone or Pyramid. RULE. — Multiply the area of the base by the... | |
| |