 Divide the first term of this remainder by the first term of the divisor, obtaining the second term of the quotient. Multiply the divisor by the second term of the quotient and subtract, obtaining a second remainder. 5. Continue in this manner until...  First Principles of Algebra: Elementary Course - Page 150by Herbert Ellsworth Slaught, Nels Johann Lennes - 1912 - 280 pagesFull view - About this book
 | Charles Davies - Algebra - 1839 - 272 pages
...dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by the second term, and subtract the product from the result of the first operation. Continue the same process until you... | |
 | Charles Davies - Algebra - 1842 - 284 pages
...dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by the second term, and subtract the product from the result of the first operation. Continue the same process until you... | |
 | William Scott - Algebra - 1844 - 568 pages
...quotient. . Divide the first term of the remainder by the first term of the divisor; the result is the second term of the quotient. Multiply the divisor by the second term of the quotient, and subtract the product from the first remainder. Repeat the process of dividing the first terms of the successive... | |
 | Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...remainder. Divide the first term of the remainder by the first term of the divisor, and the quotient will be the second term of the quotient ; multiply the divisor by the second term of the quotient, subtract the product from the last remainder, and bring down the new remainder ; divide its first term... | |
 | Charles Davies - Algebra - 1848 - 302 pages
...dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by the second term, and subtract the product from the result of the first operation. Continue the same process until you... | |
 | Theodore Strong - Algebra - 1859 - 570 pages
...divide the first term of the new dividend by the first term of the divisor, and the result will le the second term of the quotient ; multiply the divisor...by the second term, of the quotient, and subtract the terms of the product from the corresponding terms of the first new dividend. 4. Then to the remainder... | |
 | Charles Davies - Algebra - 1861 - 322 pages
...dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient; multiply the divisor by the second term, and subtract the product from the result of the first operation., Continue the same process until you... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1915 - 402 pages
...ascending) powers of some common tetter. As the division proceeds, arrange each remainder in the same way. 2. Divide the first term of the dividend by the first...contain as a factor the first term of the divisor. ORAL EXERCISES Arrange each of the following in descending powers of the letter involved : 2. 8 a -... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1915 - 412 pages
...Multiply the first term of the quotient by the divisor and subtract the product from the dividend. i. Divide the first term of this remainder by the first...contain as a factor the first term of the divisor. ORAL EXERCISES Arrange each of the following in descending powers of the letter involved : 1. 16ж-... | |
 | Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1916 - 280 pages
...Multiply the divisor by the first term of the quotient and subtract the product from the dividend. i. Divide the first term of this remainder by the first...second remainder. 5. Continue in this manner until tlie last remainder is zero, or until a remainder is found whose first term does not contain as a factor... | |
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