 | John Bonnycastle - Geometry - 1829 - 256 pages
...CASE HI. When the conjugate, ordinate, and abscissa are known, to find the transverse. RULE.t - 1. To or from the semi-conjugate, according as the greater...less abscissa is used, add, or subtract the square * This rule in algebraic terms is as follows : The greater abtttt scissa x = ~-\ — V ics «2 or the... | |
 | John Bonnycastle - Measurement - 1833 - 310 pages
...is as follows: <=(c + 2 root of the difference of the squares of the ordinatc and send conjugate. 2. Then, as this sum or difference, is to the abscissa, So is the conjugate to the transverse. EXAMPLES. . 1. The conjugate diameter CD is 40, the ordinate EP is 16, and the abscissa FB 24 : required... | |
 | William Grier - Mechanical engineering - 1832 - 366 pages
...therefore, (160 X 40) i : 60 : : 200 : 150 = the conjugate axis. 4. To find the transverse axis. Take the square root of the difference of the squares of the ordinate and half conjugate, and add to this the half conjugate if the lesser abscissa is used, but subtract the... | |
 | Tobias Ostrander - Measurement - 1834 - 182 pages
...ordinate are given, to find the abscissa. Rule — As the conjugate diameter is to the transverse, so is the square root of the difference of the squares of the ordinate and semi-conjugate to the distance between the ordinate and centre ; this distance being added to and subtracted from... | |
 | Ireland commissioners of nat. educ - 1834 - 370 pages
...conjugate, and ordinate, to find the abscissas. RULE. As the conjugate is to the transverse diameter, so is the square root of the difference of the squares of the ordinate and semi -conjugate, to the distance between the ordinate and centre. Then this distance being added to,... | |
 | William Grier - Mechanical engineering - 1836 - 384 pages
...160, then, v/(160 X 40) : 60 : 200 : 150 = the conjugate axis. 4. To find the transverse axis. Take the square root of the difference of the squares of the ordinate and half conjugate, and add to this the half conjugate if the lesser absciss is used, but subtract the... | |
 | Commissioners of National Education in Ireland - Measurement - 1837 - 290 pages
...conjugate, and ordinate, to find the abscissas. RULE. As the conjugate is to the transverse diameter, so is the square root of the difference of the squares of the ordinate and semi-conjugate, to the distance between the ordinate and centre. Then this distance being added to, and subtracted... | |
 | John Bonnycastle, Benjamin Hallowell - Measurement - 1839 - 100 pages
...14 : 10=the ordinale required. CASE п. — FACE 96. Ex. 2. Here <J 12.5a— 10»= v/56.25=7.5=the square root of the difference of the squares of the ordinate and semi-conjugate, And 25 : 35 :: 7.5 : 10.5=the distance between the ordinate and centre, Hence semi-transverse 17.5... | |
 | William Grier - Mechanical engineering - 1842 - 320 pages
...160, then, v/(160 X 40) : 60 :: 200 : 150 = the conjugate axis. 4. To find the transverse axis. Take the square root of the difference of the squares of the ordinate and half conjugate, and add to this the half conjugate if the lesser absciss is used, but subtract the... | |
 | John Bonnycastle - Measurement - 1843 - 122 pages
...25 : : 14 : 10=the ordinale required. CASE II. — PAGE 95. Ex. 2. Here Via.52— 102= 756.25=7.5 = the square root of the difference of the squares of the ordinate and semi-conjugate, And 25 : 35 : : 7.5 : 10.5 = the distance between the ordinate and centre, Hence semi-transverse 17.5... | |
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X 40) : 60 : 200 : 150 = the conjugate axis. 4. To find the transverse axis. Take the square root of the difference of the squares of the ordinate and half conjugate, and add to this the half conjugate if the lesser absciss is used, but subtract the half... 
